在 django admin 中将 json 文本显示为友好列表

发布于 2024-09-08 10:06:31 字数 616 浏览 4 评论 0 原文

我在模型中有一个 JSONField (http://djangosnippets.org/snippets/1478/) ，我试图找出向管理员用户显示数据而不是 json 的最佳方式。

有谁知道在 django admin 中执行此操作的最佳方法？

例如，我想要

{u'field_user_name': u'foo bar', u'field_email': u'[电子邮件受保护]'}

显示为

field_user_name = foo bar
field_email = [email protected]

原文

I have a JSONField (http://djangosnippets.org/snippets/1478/) in a model and I'm trying to find out the best way to display the data to the admin user rather than json.

Does anyone know the best way to do this in django admin?

For instance, I would like

{u'field_user_name': u'foo bar', u'field_email': u'[email protected]'}

to display as

field_user_name = foo bar
field_email = [email protected]

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静若繁花 2024-09-15 10:06:32

也许创建一个自定义小部件？

class FlattenJsonWidget(TextInput):
    def render(self, name, value, attrs=None):
        if not value is None:
            parsed_val = ''
            for k, v in dict(value):
                parsed_val += " = ".join([k, v])
            value = parsed_val
        return super(FlattenJsonWidget, self).render(name, value, attrs)

Perhaps create a custom widget?

class FlattenJsonWidget(TextInput):
    def render(self, name, value, attrs=None):
        if not value is None:
            parsed_val = ''
            for k, v in dict(value):
                parsed_val += " = ".join([k, v])
            value = parsed_val
        return super(FlattenJsonWidget, self).render(name, value, attrs)

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尴尬癌患者 2024-09-15 10:06:32

也许您应该创建一个模板过滤器来执行此操作：

from django import template
from django.utils import simplejson as json

register = template.Library()

@register.filter
def json_list(value):
    """
    Returns the json list formatted for display
    Use it like this :

    {{ myjsonlist|json_list }}
    """
    try:
        dict = json.loads(value)
        result = []
        for k, v in dict.iteritems():
            result.append(" = ".join([k,v]))
        return "<br/>".join(result)
    except:
        return value

Maybe you should create a template filter to do this :

from django import template
from django.utils import simplejson as json

register = template.Library()

@register.filter
def json_list(value):
    """
    Returns the json list formatted for display
    Use it like this :

    {{ myjsonlist|json_list }}
    """
    try:
        dict = json.loads(value)
        result = []
        for k, v in dict.iteritems():
            result.append(" = ".join([k,v]))
        return "<br/>".join(result)
    except:
        return value

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