从另一个 JavaScript 中减去一次时前导零

Question

function setValue() { 
var startTime = document.getElementById('ToilA'); 
var endTime = document.getElementById('EndHours'); startTime = startTime.value.split(":"); 
var startHour = parseInt(startTime[0], 10); 
var startMinutes = parseInt(startTime[1], 10); 
endTime = endTime.value.split(":"); 
var endHour = parseInt(endTime[0], 10); 
var endMinutes = parseInt(endTime[1], 10); 
//var hours, minutes; 
var today = new Date(); 
var time1 = new Date(2000, 01, 01, startHour, startMinutes, 0); 
var time2 = new Date(2000, 01, 01, endHour, endMinutes, 0); var milliSecs = (time2 - time1); 
msSecs = (1000); 
msMins = (msSecs * 60); 
msHours = (msMins * 60); 
numHours = Math.floor(milliSecs/msHours); 
numMins = Math.floor((milliSecs - (numHours * msHours)) / msMins); 
numSecs = Math.floor((milliSecs - (numHours * msHours) - (numMins * msMins))/ msSecs); numSecs = "0" + numSecs;
numMins = "0" + numMins;
DateCalc = (numHours + ":" + numMins); 

document.getElementById('CalculateHours').value = DateCalc; }

我对这段代码还有一个问题，当分钟部分超过 10 时，有一个前导 0。

因此它返回类似 11:013 而不是 11:13 的内容，这可以用数学来解决吗？或者 if 语句会解决这个问题吗？就像如果项目数量> 2、删除第一项？

我本来打算在提交表单时编写一个 PHP 脚本来删除它，但它看起来不太好。

Answer 1

将 numMins = "0" + numMins 更改为

if (numMins < 10)
    numMins = "0" + numMins;

Answer 2

if (numSecs < 10)
      numSecs = "0" + numSecs;
      if  (numMins < 10)
      numMins = "0" + numMins;