找到一个 1x3 矩阵，结果为零矩阵

发布于 2024-09-08 08:42:14 字数 506 浏览 6 评论 0原文

我知道一个 3x3 矩阵 M，我想找到一个 1x3 矩阵 P。给定的条件是：

[p1 p2 p3]*[m11 m12 m13; m21 m22 m23; m31 m32 m33] = [0 0 0]

给定是 [m11 m12 m13; m21 m22 m23； m31 m32 m33]

我必须使用 Matlab 找到 [p1 p2 p3] 的非平凡（非零）解。

我想在 Matlab 中完成，因为它是代码的一部分。如果需要，还给出一个条件：
p1 + p2 + p3 = 1

PS： 我尝试过“inv”函数，它给出了矩阵的逆矩阵，但是它给出了微不足道的解决方案。我还阅读了 'svg' 和 'null' 函数，但我怀疑它们是否适用于 Ax=B 类型，我的问题是 xA=B 类型。

原文

I know a 3x3 matrix M, and I want to find a 1x3 matrix P. The given condition is:

[p1 p2 p3]*[m11 m12 m13; m21 m22 m23; m31 m32 m33] = [0 0 0]

Given is [m11 m12 m13; m21 m22 m23; m31 m32 m33]

I have to find non trivial (non-zero) solution of [p1 p2 p3] using Matlab.

I am wanting to be done in Matlab because its part of a code. If needed, given also is a condition:
p1 + p2 + p3 = 1

P.S: I have tried the 'inv' function which gives the inverse of a matrix, however it is giving trivial solution. I have also read about the 'svg' and 'null' functions, but I doubt that they are meant for the Ax=B type, where as my problem is xA=B type.

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