访问修饰符适用于静态类函数吗？
我刚刚遇到了受保护的静态类函数的代码，如下所示：
class C {
...
protected:
static int fun() { ... }
};
我很好奇静态类函数是否可以具有访问修饰符，这意味着什么？因为它们是类全局变量而不是预实例。
谢谢，博达·西多。
I just came across code that had protected static class functions, as in:
class C {
...
protected:
static int fun() { ... }
};
I got curious if static class functions could have access modifiers and what would it mean? Since they are class globals and not pre-instance.
Thanks, Boda Cydo.
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C++ 中的访问修饰符不能针对每个实例工作。他们总是按班级工作。一直都是这样。这使得它们也适用于静态成员是完全合乎逻辑的。
这是一个相当流行的误解，认为 C++ 中的访问保护应该以某种方式针对每个实例起作用，这似乎也激发了您的问题。
Access modifiers in C++ do not work per-instance. They always work per-class. That is how it's always been. Which makes it perfectly logical to have them apply to static members as well.
It is a rather popular misconception that access protection in C++ is somehow supposed to work per-instance, which seems to be what inspired your question as well.
它仍然具有相同的目的：只有派生类可以调用该静态函数。
It still serves the same purpose: Only derived classes can call that static function.
这意味着受保护：静态函数可以从该类的其他成员函数或派生类的成员函数访问。
It means protected: static functions can be accessed from other member functions of that class or from the member functions of the derived classes.