在 Python 中使用具有可变长度未命名参数的命名参数
如果这个问题已经被问/回答了，我深表歉意，我本以为会出现这种情况，但无法找到任何相关的问题...
我想创建一个 python 函数，它接受两个强制参数，一个命名参数，以及一些未知数量的其他非命名参数：
def my_function(arg1, arg2, arg3=None, *other_args):
pass
这在 Python 2.x 中可能吗？
除了可变长度参数列表之外，函数还可以接受命名参数吗？
我相信答案是“否”，在这种情况下，我认为唯一可用的解决方案类似于以下内容：
def my_function(arg1, arg2, **kwargs):
arg3 = kwargs["arg3"]
other_args = kwargs["other_args"]
这是正确的吗？
I apologize if this question has already been asked/answered, I would have expected that to be the case but was unable to find any related questions...
I'd like to create a python function that takes two mandatory arguments, one named argument, and some unknown number of other, non-named arguments as so:
def my_function(arg1, arg2, arg3=None, *other_args):
pass
Is this possible in Python 2.x?
Can a function accept named arguments in addition to a variable length argument list?
I believe the answer is 'no', in which case I'm thinking the only solution available to me would be something similar to the following:
def my_function(arg1, arg2, **kwargs):
arg3 = kwargs["arg3"]
other_args = kwargs["other_args"]
Is that correct?
如果你对这篇内容有疑问，欢迎到本站社区发帖提问 参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱，如果其他用户或者作者回复了您的评论，将不能在第一时间通知您！
发布评论
评论（1）
该语法当然是有效的，但我认为您的意思是您可以编写函数签名，使得 arg3 仅在用作命名参数时才绑定（例如 my_function(1, 2, arg3 = 3))，否则让前两个参数之后的所有参数都被
*other_args捕获，在这种情况下答案是否定的。可选参数可以通过命名来指定，但它们也像普通参数一样具有位置性，并且如果有足够的参数可用，则在使用*args或**kwargs 等包罗万象的参数之前填充它们。我可能会像你一样使用关键字参数来编写它
That syntax is certainly valid, but I think you mean can you write the function signature such that
arg3is only bound if it's used as a named parameter (e.g.my_function(1, 2, arg3 = 3)), and otherwise to have all arguments past the first two be caught by*other_args, in which case the answer is no. Optional arguments can be specified by naming, but they're also positional like normal arguments and are filled in if enough parameters are available, before resorting to catch-alls like*argsor**kwargs.I would probably write it exactly as you did, using keyword arguments