如何将弹出窗口放置在屏幕的右上角

Question

我想要做的是更改窗口的大小并在其旁边创建一个窗口，以便它们彼此完全相邻。从这个意义上说，我需要将新窗口定位到屏幕的右上角，我这样做的方式不起作用（代码如下），我需要帮助:)

function () { 
   var viewportwidth = document.documentElement.clientWidth;
   var viewportheight = document.documentElement.clientHeight;
   window.resizeBy(-300,0); 
   window.open("something.htm",
     "mywindow",
     "width=300,
     height=viewportheight,
     left=(viewportwidth - 300),
     top=0,
     screenX=0,
     screenY=0"); 
}

Answer 1

var viewportwidth = document.documentElement.clientWidth;
var viewportheight = document.documentElement.clientHeight;
window.resizeBy(-300,0);
window.moveTo(0,0);

window.open("http://google.com",
            "mywindow",
            "width=300,left="+(viewportwidth-300)+",top=0");

Answer 2

我还没有测试过实际的窗口大小数学；不确定这是否正确。但您遇到的第一个明显的问题是将变量嵌入到对 window.open 的调用中。尝试更改

  window.open("something.htm", "mywindow",
 "width=300, height=viewportheight, left=(viewportwidth - 300), top=0, screenX=0, screenY=0"); 

为

  window.open("something.htm", "mywindow",
 "width=300, height=" + viewportheight + ", left=" + (viewportwidth - 300) + ", top=0, screenX=0, screenY=0");

基本上，如果您希望变量或数学得到解析，它们必须位于字符串之外。