按降序进行堆排序不起作用

发布于 2024-09-08 01:31:27 字数 2485 浏览 3 评论 0原文

我已经看了几个小时了,但无法弄清楚。如果 heapify 函数中的比较更改为大于,则输出应按升序排列。我希望我的列表按降序排序,但它没有使用以下代码给出正确的输出:

#include <stdlib.h>
#include <stdio.h>
#include <string.h>

typedef struct stuff {
    char *str;
}stuff_t;

void heapify(stuff_t *stuff_array, int i, int n) 
{
    stuff_t temp;
    int left, right, max;

    left = 2*i;
    right = left + 1;
    max = i;
    if (left < n)
        if (strtod(stuff_array[left].str, NULL) < strtod(stuff_array[i].str, NULL))
            max = left;
    if (right < n)
        if (strtod(stuff_array[right].str, NULL) < strtod(stuff_array[max].str, NULL))
            max = right;

    if (max != i)
    {
        temp = stuff_array[i];
        stuff_array[i] = stuff_array[max];
        stuff_array[max] = temp;
        heapify(stuff_array, max, n);
    }
}

void heapsort(stuff_t *stuff_array)
{
    short i,N;
    stuff_t temp; 

    N = 0;
    while (stuff_array[N].str)
        N++;

    for (i = (N/2)-1; i >= 0; i--)
        heapify(stuff_array, i, N);

    for (i = N-1; i >= 1; i--) {
        temp = stuff_array[0];
        stuff_array[0] = stuff_array[i];
        stuff_array[i] = temp;
        heapify(stuff_array, 0, i);
    }
}

int main (int argc, char* argv[])
{
    int i;
    stuff_t *s_list = calloc(4, sizeof(stuff_t));
    stuff_t *s_list1 = calloc(8, sizeof(stuff_t));
    s_list[0].str = "9.3";
    s_list[1].str = "9.3";
    s_list[2].str = "7.8";

    printf("before: ");
    for (i = 0; i < 3; i++)
        printf("%s, ", s_list[i]);
    printf("\n");

    heapsort(s_list);

    printf("after: ");
    for (i = 0; i < 3; i++)
        printf("%s, ", s_list[i]);
    printf("\n");

    s_list1[0].str = "7.5";
    s_list1[1].str = "10.0";
    s_list1[2].str = "10.0";
    s_list1[3].str = "8.3";
    s_list1[4].str = "6.5";
    s_list1[5].str = "5.0";
    s_list1[6].str = "4.6";

    printf("before: ");
    for (i = 0; i < 3; i++)
        printf("%s, ", s_list1[i]);
    printf("\n");

    heapsort(s_list1);

    printf("after: ");
    for (i = 0; i < 7; i++)
        printf("%s, ", s_list1[i]);
    printf("\n");
    return 0;
}

程序输出:

// using less than comparison
before: 9.3, 9.3, 7.8,
after: 9.3, 7.8, 9.3,
before: 7.5, 10.0, 10.0,
after: 10.0, 10.0, 8.3, 7.5, 6.5, 4.6, 5.0,

// using greator than comparison
before: 9.3, 9.3, 7.8,
after: 7.8, 9.3, 9.3,
before: 7.5, 10.0, 10.0,
after: 4.6, 5.0, 6.5, 7.5, 8.3, 10.0, 10.0,

I have been looking at this for hours and can't figure this out. If the comparisons in the heapify function are changed to greater than, then the output is in increasing order as it should be. I want my list to be sorted in decreasing order though and it's not giving the correct output using the below code:

#include <stdlib.h>
#include <stdio.h>
#include <string.h>

typedef struct stuff {
    char *str;
}stuff_t;

void heapify(stuff_t *stuff_array, int i, int n) 
{
    stuff_t temp;
    int left, right, max;

    left = 2*i;
    right = left + 1;
    max = i;
    if (left < n)
        if (strtod(stuff_array[left].str, NULL) < strtod(stuff_array[i].str, NULL))
            max = left;
    if (right < n)
        if (strtod(stuff_array[right].str, NULL) < strtod(stuff_array[max].str, NULL))
            max = right;

    if (max != i)
    {
        temp = stuff_array[i];
        stuff_array[i] = stuff_array[max];
        stuff_array[max] = temp;
        heapify(stuff_array, max, n);
    }
}

void heapsort(stuff_t *stuff_array)
{
    short i,N;
    stuff_t temp; 

    N = 0;
    while (stuff_array[N].str)
        N++;

    for (i = (N/2)-1; i >= 0; i--)
        heapify(stuff_array, i, N);

    for (i = N-1; i >= 1; i--) {
        temp = stuff_array[0];
        stuff_array[0] = stuff_array[i];
        stuff_array[i] = temp;
        heapify(stuff_array, 0, i);
    }
}

int main (int argc, char* argv[])
{
    int i;
    stuff_t *s_list = calloc(4, sizeof(stuff_t));
    stuff_t *s_list1 = calloc(8, sizeof(stuff_t));
    s_list[0].str = "9.3";
    s_list[1].str = "9.3";
    s_list[2].str = "7.8";

    printf("before: ");
    for (i = 0; i < 3; i++)
        printf("%s, ", s_list[i]);
    printf("\n");

    heapsort(s_list);

    printf("after: ");
    for (i = 0; i < 3; i++)
        printf("%s, ", s_list[i]);
    printf("\n");

    s_list1[0].str = "7.5";
    s_list1[1].str = "10.0";
    s_list1[2].str = "10.0";
    s_list1[3].str = "8.3";
    s_list1[4].str = "6.5";
    s_list1[5].str = "5.0";
    s_list1[6].str = "4.6";

    printf("before: ");
    for (i = 0; i < 3; i++)
        printf("%s, ", s_list1[i]);
    printf("\n");

    heapsort(s_list1);

    printf("after: ");
    for (i = 0; i < 7; i++)
        printf("%s, ", s_list1[i]);
    printf("\n");
    return 0;
}

program output:

// using less than comparison
before: 9.3, 9.3, 7.8,
after: 9.3, 7.8, 9.3,
before: 7.5, 10.0, 10.0,
after: 10.0, 10.0, 8.3, 7.5, 6.5, 4.6, 5.0,

// using greator than comparison
before: 9.3, 9.3, 7.8,
after: 7.8, 9.3, 9.3,
before: 7.5, 10.0, 10.0,
after: 4.6, 5.0, 6.5, 7.5, 8.3, 10.0, 10.0,

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评论(1

度的依靠╰つ 2024-09-15 01:31:27

如果从 0 开始计数,则不能使用 i*2 和 i*2+1 作为子级的地址。问题是 2*0 = 0(左子级将与父级相同)。

You cannot use i*2 and i*2+1 as addresses for children if you start counting from 0. The problem is that 2*0 = 0 (left child will be the same as the parent).

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