如何用 PHP 替换字符串中的多个 %tags%

发布于 2024-09-07 22:54:58 字数 378 浏览 1 评论 0原文

替换 PHP 字符串中一组短标签的最佳方法是什么，例如：

$return = "Hello %name%, thank you for your interest in the %product_name%.  %representative_name% will contact you shortly!";

我将定义 %name% 是某个字符串，来自数组或对象，例如：

$object->name;
$object->product_name;

等等。

我知道我可以运行 str_replace在字符串上多次，但我想知道是否有更好的方法来做到这一点。

谢谢。

原文

What is the best way of replacing a set of short tags in a PHP string, example:

$return = "Hello %name%, thank you for your interest in the %product_name%.  %representative_name% will contact you shortly!";

Where I would define that %name% is a certain string, from an array or an object such as:

$object->name;
$object->product_name;

etc..

I know I could run str_replace multiple times on a string, but I was wondering if there is a better way of doing that.

Thanks.

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偷得浮生 2024-09-14 22:54:58

如果您知道要替换的占位符，str_replace() 似乎是一个理想的选择。这需要运行一次而不是多次。

$input = "Hello %name%, thank you for your interest in the %product_name%.  %representative_name% will contact you shortly!";

$output = str_replace(
    array('%name%', '%product_name%', '%representative_name%'),
    array($name, $productName, $representativeName),
    $input
);

str_replace() seems an ideal option if you know the placeholders you intend to replace. This need be run just once not multiple times.

$input = "Hello %name%, thank you for your interest in the %product_name%.  %representative_name% will contact you shortly!";

$output = str_replace(
    array('%name%', '%product_name%', '%representative_name%'),
    array($name, $productName, $representativeName),
    $input
);

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梦晓ヶ微光ヅ倾城 2024-09-14 22:54:58

这个类应该这样做：

<?php
class MyReplacer{
  function __construct($arr=array()){
    $this->arr=$arr;
  }

  private function replaceCallback($m){
    return isset($this->arr[$m[1]])?$this->arr[$m[1]]:'';
  }

  function get($s){  
    return preg_replace_callback('/%(.*?)%/',array(&$this,'replaceCallback'),$s);
  }

}


$rep= new MyReplacer(array(
    "name"=>"john",
    "age"=>"25"
  ));
$rep->arr['more']='!!!!!';  
echo $rep->get('Hello, %name%(%age%) %notset% %more%');

This class should do it:

<?php
class MyReplacer{
  function __construct($arr=array()){
    $this->arr=$arr;
  }

  private function replaceCallback($m){
    return isset($this->arr[$m[1]])?$this->arr[$m[1]]:'';
  }

  function get($s){  
    return preg_replace_callback('/%(.*?)%/',array(&$this,'replaceCallback'),$s);
  }

}


$rep= new MyReplacer(array(
    "name"=>"john",
    "age"=>"25"
  ));
$rep->arr['more']='!!!!!';  
echo $rep->get('Hello, %name%(%age%) %notset% %more%');

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廻憶裏菂餘溫 2024-09-14 22:54:58

最简单和最短的选项是带有“e”开关的 preg_replace

$obj = (object) array(
    'foo' => 'FOO',
    'bar' => 'BAR',
    'baz' => 'BAZ',
);

$str = "Hello %foo% and %bar% and %baz%";
echo preg_replace('~%(\w+)%~e', '$obj->$1', $str);

The simplest and shortest option is preg_replace with the 'e' switch

$obj = (object) array(
    'foo' => 'FOO',
    'bar' => 'BAR',
    'baz' => 'BAZ',
);

$str = "Hello %foo% and %bar% and %baz%";
echo preg_replace('~%(\w+)%~e', '$obj->$1', $str);

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圈圈圆圆圈圈 2024-09-14 22:54:58

来自 str_replace 的 PHP 手册：

如果search和replace是数组，那么
str_replace() 从每个中获取一个值
数组并使用它们进行搜索和
替换主题。如果替换有
比搜索更少的值，然后
其余部分使用空字符串
替换值。如果搜索是一个
array 和replace 是一个字符串，那么
该替换字符串用于
搜索的每个值。反过来
但这没有意义。

http://php.net/manual/en/function.str-replace。 php