django在模板中调用无请求视图函数

发布于 2024-09-07 19:19:38 字数 1283 浏览 2 评论 0原文

我正在制作一些视图函数来计算社区中一个用户的排名。我的问题是我想在其个人资料中显示传入每个用户的排名，但我不知道如何，因为我没有请求和 render_to_response （因为我猜它们不需要）我的代码：

def calculate_questions_vote(request):
    useranswer = Answer.objects.filter (answer_by = request.user)
    positive_votes = VoteUpAnswer.objects.filter(answer = useranswer)
    negative_votes = VoteDownAnswer.objects.filter(answer = useranswer)
    question_vote_rank = sum(positive_votes) - sum(negative_votes.count)
        return question_vote_rank

def calculate_replies(request):
    the_new = News.objects.filter(created_by = request.user)
    reply = Reply.objects.filter(reply_to = the_new)
    reply_rank = sum(reply)
        return reply_rank

def calculate_votes(request):
    the_new = News.objects.filter(created_by = request.user)
    vote = Vote.objects.filter(voted = the_new)
    vote_rank = sum(vote)
        return vote_rank

def personal_rank(request):
    personal_rank = question_vote_rank + reply_rank + vote_rank
        return personal_rank

在 UserProfiles 中：

user = request.user  
personal_rank = calculate_questions_vote(user) + calculate_replies(user) + personal_rank(user)

但我的错误是：

错误绑定参数 0 - 可能不受支持的类型。

mt方法正确吗？我应该如何调用 profile_view def 中的排名函数？

谢谢！

原文

I am making some view functions to calculate the rank of one user in a community.
My problem is that i want to display the rank afferent to each user, in its profile, and i don't know how, since i don;t have a request and a render_to_response (cause i guessed they are not needed)
my code:

def calculate_questions_vote(request):
    useranswer = Answer.objects.filter (answer_by = request.user)
    positive_votes = VoteUpAnswer.objects.filter(answer = useranswer)
    negative_votes = VoteDownAnswer.objects.filter(answer = useranswer)
    question_vote_rank = sum(positive_votes) - sum(negative_votes.count)
        return question_vote_rank

def calculate_replies(request):
    the_new = News.objects.filter(created_by = request.user)
    reply = Reply.objects.filter(reply_to = the_new)
    reply_rank = sum(reply)
        return reply_rank

def calculate_votes(request):
    the_new = News.objects.filter(created_by = request.user)
    vote = Vote.objects.filter(voted = the_new)
    vote_rank = sum(vote)
        return vote_rank

def personal_rank(request):
    personal_rank = question_vote_rank + reply_rank + vote_rank
        return personal_rank

and in UserProfiles:

user = request.user  
personal_rank = calculate_questions_vote(user) + calculate_replies(user) + personal_rank(user)

but my error is:

Error binding parameter 0 - probably unsupported type.

Is mt approach correct? How should i call the rank function in the profile_view def ?

Thanks!

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一枫情书 2024-09-14 19:19:38

您可以在视图中调用该函数，例如 rank = individual_rank(reuest.user) 并将 rank 添加到您的上下文中。
我不会将此函数称为“视图”函数，因为它们不处理请求，也不返回 HttoResponce；它们是更多的“帮助”功能，如果它们处理单独的实体（例如新闻和投票），那么它们也不属于模型。他们的下降地点是例如。 utils.py。您可以从 views.py 中导入它们，并以用户作为参数调用它们（如果是实际用户，则为 request.user）。
这是有道理的，你不能从任何地方访问 request ，因为这迫使你更多地保留类似 mvc 的设计，如果你需要在某个地方请求，你需要从原始视图函数传递它！
您应该将最后一个函数更改为：

def personal_rank(user):
    personal_rank = calculate_questions_vote(user) + \
                    calculate_replies(user) + \
                    calculate_votes(user)
    return personl_rank

如果您有类似的东西，您还可以将最后一个函数添加到您的 User 或 UserProfile 模型类中，然后调用例如。 my_user.personal_rank() 或 my_user.get_profile().personal_rank()。

YOu can call the function in your view like rank = personal_rank(reuest.user) and add rank to your context then.
I wouldnt call this functions "view"-functions, since they are not dealing with a request nor are they returning a HttoResponce; they are more "helper" functions and also don't belong to a model if they are dealing with seperate entities (eg. News & Vote). A descent place for them would be eg. utils.py. You import them from there in your views.py and call them with the user as parameter (if it's the actual user it's request.user).
It makes sense that you can't access request from everywhere, because this forces you to keep more to a mvc-like design, if you need request somewhere you need to pass it on from your original view function!
You should change your last function to:

def personal_rank(user):
    personal_rank = calculate_questions_vote(user) + \
                    calculate_replies(user) + \
                    calculate_votes(user)
    return personl_rank

You could also add this last function to your User or UserProfile model class if you have something like that and then call eg. my_user.personal_rank() or my_user.get_profile().personal_rank().

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一人独醉 2024-09-14 19:19:38

lazerscience对你的疑问给出了很好的解释。我只是想指出一些可能的性能问题。

请注意，为每个用户调用此方法会产生 7 个查询。如果您的案例要显示所有用户的排名，则可能需要花费大量时间。我建议进行一些缓存（就像在 StackOverflow 中一样）。这里有很多选项，例如，您可以将特殊的 rank 字段分配给 User 模型（或 UserProfile 如果 User > 是auth.User），您可以在其中存储预先计算的排名（在某些操作之后计算，例如新闻保存或在某些计划的时间间隔内）。