如何获取 List来自这个 XML？

发布于 2024-09-07 10:41:26 字数 789 浏览 5 评论 0原文

我有一个类似于以下内容的 XML 块：

<factsheet>
<bilcontents >
  <config name="1" />
</bilcontents>

<singlefactsheet includeInBook="true">
  <config name="7" />
  <fund id="630" />
</singlefactsheet>

<doubleFactsheet includeInBook="true">
  <config name="8" />
  <fund id="623" />
  <fund id="624" />
</doubleFactsheet>

<tripplefactsheet includeInBook="true">
  <config name="6" />
  <fund id="36" />
  <fund id="37" />
  <fund id="38" />
</tripplefactsheet>
</factsheet>

Is it possible for me to get a list of XElements that contains every XElements, as long as includeInBook="true", and with every element I can然后根据节点的类型进行处理。

原文

I have a block of XML similar to the following:

<factsheet>
<bilcontents >
  <config name="1" />
</bilcontents>

<singlefactsheet includeInBook="true">
  <config name="7" />
  <fund id="630" />
</singlefactsheet>

<doubleFactsheet includeInBook="true">
  <config name="8" />
  <fund id="623" />
  <fund id="624" />
</doubleFactsheet>

<tripplefactsheet includeInBook="true">
  <config name="6" />
  <fund id="36" />
  <fund id="37" />
  <fund id="38" />
</tripplefactsheet>
</factsheet>

Is it possible for me to get a list of XElements that contains each of these, as long as includeInBook="true", and with each element I can then deal with it based on the type of node.

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智商已欠费 2024-09-14 10:41:26

绝对：

 var list = doc.Root
               .Elements()
               .Where(x => (bool?) x.Attribute("includeInBook") == true)
               .ToList();

顺便说一句，处理可为空的布尔值可能有点奇怪。 lambda 表达式的另一种方法可以是：

x => (bool?) x.Attribute("includeInBook") ?? false

或者

x => (string) x.Attribute("includeInBook") == "true"

Absolutely:

 var list = doc.Root
               .Elements()
               .Where(x => (bool?) x.Attribute("includeInBook") == true)
               .ToList();

Dealing with nullable Booleans can be a little odd, btw. An alternative approach for the lambda expression could be:

x => (bool?) x.Attribute("includeInBook") ?? false

x => (string) x.Attribute("includeInBook") == "true"

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昇り龍 2024-09-14 10:41:26

这就是我的成果，尽管乔恩几乎抢先一步

var inBook = nodes.Descendants()
    .Where(xx => xx.Attribute("includeInBook") != null)
    .Select(xx => xx).ToList();

This is what I worked out, though Jon pretty much beat me to the punch

var inBook = nodes.Descendants()
    .Where(xx => xx.Attribute("includeInBook") != null)
    .Select(xx => xx).ToList();

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爱她像谁 2024-09-14 10:41:26

您应该考虑为此 XML 创建数据结构并使用“序列化”。这将是与该数据模型交互的更简洁的方式。只是需要考虑的事情...

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弱骨蛰伏 2024-09-14 10:41:26

或者，您可以使用内置的 XPath 扩展方法（它们位于 System.Xml.Xpath 中：

XDocument doc;
// ...
var includeInBook = doc.XPathSelectElements("/factsheet/*[@includeInBook = 'true']")

读为：

/factsheet：选择元素 'factsheet'
< code>/*：然后选择所有子元素
[ ... ]：将方括号读作“where”
- @includeInBook = 'true'：属性“includeInBook”的内容等于“true”

Alternately, you could use the built-in XPath extension methods methods (they live in System.Xml.Xpath:

XDocument doc;
// ...
var includeInBook = doc.XPathSelectElements("/factsheet/*[@includeInBook = 'true']")

Read as:

/factsheet: select the element 'factsheet'
/*: then choose all children
[ ... ]: read square brackets as "where"
- @includeInBook = 'true': the attribute "includeInBook" has content equal to 'true'

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