两个标签之间的 XQuery 提取

发布于 2024-09-07 04:51:24 字数 1201 浏览 1 评论 0原文

我目前正在研究从 HTML 中提取数据。我想提取两个

标记之间的文本。

         <p class="xfHeading"><b>XYZ:</b></p> 
            <p>asdfghjk</p>  
            <p>sdsdsd</p>  
            <p>asdvcvcfghjk</p>  

         <p class="xfHeading"><b>ABC:</b></p> 
            <P>fvgbhnjm</P>  

         <p class="xfHeading"><b>PQR:</b></p> 
            <ul> 

            </ul> 

         <p class="xfHeading"><b>MNO:</b></p> 
             <ul> 
                <li>jdjshdj</li>  
             </ul>

输出应该是：

asdfghjk

sdsdsd

asdvcvcfghjk

一种方法是：

/p[class="xfHeading"]/following-sibling::p[0]|/p[class="xfHeading"]/following-sibling::p[1]|/p[class="xfHeading"]/following-sibling::p[2]

或

/p[class="xfHeading"]/following-sibling::p[position()<4]

但是，由于之间的内容一直在变化，我需要一个解决方案，其中两个标签之间的内容  被提取。

原文

I am currently working on extracting data from HTML. I would like to extract the text between two  tags.

         <p class="xfHeading"><b>XYZ:</b></p> 
            <p>asdfghjk</p>  
            <p>sdsdsd</p>  
            <p>asdvcvcfghjk</p>  

         <p class="xfHeading"><b>ABC:</b></p> 
            <P>fvgbhnjm</P>  

         <p class="xfHeading"><b>PQR:</b></p> 
            <ul> 

            </ul> 

         <p class="xfHeading"><b>MNO:</b></p> 
             <ul> 
                <li>jdjshdj</li>  
             </ul>

The output should be :

asdfghjk

sdsdsd

asdvcvcfghjk

One way to do this is :

/p[class="xfHeading"]/following-sibling::p[0]|/p[class="xfHeading"]/following-sibling::p[1]|/p[class="xfHeading"]/following-sibling::p[2]

/p[class="xfHeading"]/following-sibling::p[position()<4]

However since the content between keeps on changing all the time I need a solution wherein the content between the two tags  is extracted.

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与往事干杯 2024-09-14 04:51:24

使用：

(//p[@class="xfHeading"])[1]
          /following-sibling::p
             [. << (//p[@class="xfHeading"])[2]]
                 /text()

这意味着：选择第一个 pp 元素的文本节点子元素> 文档中 class 属性值为 xfHeading 的元素，同时位于文档中第二个 p 元素之前class 属性的值为 xfHeading。

Use:

(//p[@class="xfHeading"])[1]
          /following-sibling::p
             [. << (//p[@class="xfHeading"])[2]]
                 /text()

This means: Select the text-node children of all p elements that are following siblings of the first p element in the document with class attribute having value of xfHeading, and that at the same time are preceding the second p element in the document with class attribute having value of xfHeading.

回复收藏 0 原文

迟到的我 2024-09-14 04:51:24

编辑：在您澄清后，我的建议是使用 FLWOR表达式如下。这将根据标记的唯一内容查找具有正确 标记内容的

，并返回与其同级的每个
标记的文本。

for $b in //p[class="xfHeading"]/b and $p in //p[class="xfHeading"]/p
    where $b/text() = "XYZ:"
        return p/text()

请注意，// 是一个 XPATH 构造，而不是注释

旧答案：如果没有您希望结果数据是什么样子的示例，则回答问题是有点难。但是，例如，要选择 标记内的文本，您可以执行以下操作：

/p[class = "xfHeading"]/b/text()

一般来说，将 text() 附加到表达式的末尾返回相关节点内的文本。

EDIT: After your clarification, my suggestion is to use a FLWOR expression such as the following. This looks for a  with the proper  tag contents based on the unique contents of that  tag, and returns the text of each  tag that is a sibling of it.

for $b in //p[class="xfHeading"]/b and $p in //p[class="xfHeading"]/p
    where $b/text() = "XYZ:"
        return p/text()

Note that the // is an XPATH construct, not a comment

OLD ANSWER: Without an example of what you'd like the resulting data to look like, answering the question is a bit tough. However, to select, for instance, the text inside a  tag, you'd do: