计算函数回显语句的次数

Question

我有一个调用其他两个函数的函数：

class myClass{


    function myFunc(){

        for($i=0;$i<500;$i++){
            $this->func1();
            $this->func2();
        }
    }

    function func1(){
         // Does some stuff
         // echos statements, and can vary the amount of echoed statements
         while($something == true)
             echo "This is from func1, and may echo 0-1000 times";
    }

    function func2(){
         // Does some stuff
         // echos statements, and can vary the amount of echoed statements
         while($something == true)
             echo "This is from func2, and may echo 0-1000 times";
    }
}

我想做的是找到一种方法，可以获取函数回显某些内容的总次数，并获取该信息以显示在 myFunc() 中。我写了一个计数函数，但它没有按照我预期的方式工作。

有什么建议吗？

Answer 1

这是一种方法：

class myClass{
    private $count;

    function myFunc(){

        for($i=0;$i<500;$i++){
            $this->func1();
            $this->func2();
        }
    }

    function func1(){
         // Does some stuff
         // echos statements, and can vary the amount of echoed statements
         while($something == true) {
             $this->count++;
             echo "This is from func1, and may echo 0-1000 times";
         }
    }

    function func2(){
         // Does some stuff
         // echos statements, and can vary the amount of echoed statements
         while($something == true) {
             $this->count++;
             echo "This is from func2, and may echo 0-1000 times";
         }
    }
}

或者更好的方法：

class myClass{
    private $count;

    function myFunc(){

        for($i=0;$i<500;$i++){
            $this->func1();
            $this->func2();
        }
    }

    function func1(){
         // Does some stuff
         // echos statements, and can vary the amount of echoed statements
         while($something == true) {
             echoMe("This is from func1, and may echo 0-1000 times");
         }
    }

    function func2(){
         // Does some stuff
         // echos statements, and can vary the amount of echoed statements
         while($something == true) {
             echoMe("This is from func2, and may echo 0-1000 times");
         }
    }

    function echoMe($msg) {
        echo $msg;
        $this->count++;
    }
}

Answer 2

function myFunc(){
    $echo_count = 0;
    for($i=0;$i<500;$i++){
        $echo_count += $this->func1();
        $echo_count += $this->func2();
    }
    echo $echo_count;
}

function func1(){
     // Does some stuff
     // echos statements, and can vary the amount of echoed statements
     $count = 0;
     while($something == true){
         echo "This is from func1, and may echo 0-1000 times";
         $count++;
     }
     return $count;
}

function func2(){
     // Does some stuff
     // echos statements, and can vary the amount of echoed statements
     $count = 0;
     while($something == true){
         echo "This is from func2, and may echo 0-1000 times";
         $count++;
     }
     return $count;
}

Answer 3

为什么不让函数返回回显计数：

$echoCount = 0;
while ($something == true) {
    echo "This is from func1, and may echo 0-1000 times";
    $echoCount++;
}

return $echoCount;

然后在 myFunc 中，您可以累积它们：

function myFunc() {

    $totalEchoes = 0;
    for ($i=0; $i<500; $i++) {
        $totalEchoes += $this->func1() + $this->func2();
    }
}