带窗口的多重计数（子字符串） psql 8.4.4

Question

我正在尝试创建以下视图，但出现以下错误： 我可以执行 1 个计数语句（如果删除 AS“Mod0”）是否可以对多个子字符串进行计数，并将输出计数到新列？

create view portcnt as 
    select 
    address,
    datacenter,
    ifdesc,
    count(substring(ifdesc, 'Ethernet0/*')) as "Mod0",
    count(substring(ifdesc, 'Ethernet1/*')) as "Mod1",
    count(substring(ifdesc, 'Ethernet2/*')) as "Mod2",
    count(substring(ifdesc, 'Ethernet3/*')) as "Mod3",
    count(substring(ifdesc, 'Ethernet4/*')) as "Mod4",
    count(substring(ifdesc, 'Ethernet5/*')) as "Mod5",
    count(substring(ifdesc, 'Ethernet6/*')) as "Mod6"
    over (partition by address)
    from ifstatus where datacenter = 'DC' 
    and ifadminstatus = '1' and ifoperstatus = '1';
ERROR:  syntax error at or near "by"
LINE 13:  over (partition by address)

Answer 1

找到了一个有效的解决方案：

create view portcnt1 as
    select
    address,
    datacenter,
    ifdesc,
    count(substring(ifdesc, 'Ethernet0/*')) 
    over (partition by address) mod0,
    count(substring(ifdesc, 'Ethernet1/*'))
    over (partition by address) mod1,
    count(substring(ifdesc, 'Ethernet2/*'))
    over (partition by address) mod2,
    count(substring(ifdesc, 'Ethernet3/*'))
    over (partition by address) mod3,
    count(substring(ifdesc, 'Ethernet4/*'))
    over (partition by address) mod4,
    count(substring(ifdesc, 'Ethernet5/*'))
    over (partition by address) mod5,
    count(substring(ifdesc, 'Ethernet6/*'))
    over (partition by address) mod6,
    count(substring(ifdesc, 'Ethernet7/*'))
    over (partition by address) mod7,
    count(substring(ifdesc, 'Ethernet8/*'))
    over (partition by address) mod8,
    count(substring(ifdesc, 'Ethernet9/*'))
    over (partition by address) mod9
    from ifstatus
    where ifadminstatus = '1' and ifoperstatus = '1';