使用 jQuery 在单击时显示/隐藏 div

Question

我有 4 个 div，点击导航时我想显示其中一个并隐藏其他。我让它工作了，但我觉得它不像我知道的那么顺利，它绝对是我的代码需要重构！这是我所拥有的。

$('#details-speakers').click(function() {

    $('#home').slideUp('slow', function() {});
    $('#sessions-content').slideUp('slow', function() {});
    $('#cases-content').slideUp('slow', function() {});
    $('html,body').animate({scrollTop: $("#details").offset().top - 16}, 200, "swing");
  $('#speakers-content').slideDown('slow', function() {
        $('#details-speakers').addClass('selected');
        //Remove other classes
        $('#details-sessions').removeClass('selected');
        $('#details-cases').removeClass('selected');
        $('#details-workshops').removeClass('selected');
  });
});
$('#details-sessions').click(function() {

    $('#home').slideUp('slow', function() {});
    $('#speakers-content').slideUp('slow', function() {});
    $('#cases-content').slideUp('slow', function() {});
    $('html,body').animate({scrollTop: $("#details").offset().top - 16}, 200, "swing");
  $('#sessions-content').slideDown('slow', function() {
    $('#details-sessions').addClass('selected');
        //Remove other classes
        $('#details-speakers').removeClass('selected');
        $('#details-cases').removeClass('selected');
        $('#details-workshops').removeClass('selected');
  });
});
$('#details-cases').click(function() {

    $('#home').slideUp('slow', function() {});
    $('#speakers-content').slideUp('slow', function() {});
    $('#sessions-content').slideUp('slow', function() {});
    $('html,body').animate({scrollTop: $("#details").offset().top - 16}, 200, "swing");
  $('#cases-content').slideDown('slow', function() {
    $('#details-cases').addClass('selected');
        //Remove other classes
        $('#details-speakers').removeClass('selected');
        $('#details-sessions').removeClass('selected');
        $('#details-workshops').removeClass('selected');
  });
});

Answer 1

Ctrl+C 和 Ctrl+V 编程会直接导致地狱...我认为你可以做这样的事情：

var divs = $('#details-speakers, #details-sessions, #details-cases');

divs.click(function () {
    divs.not(this).add('#home').slideUp('slow');
    // animation with home and body
    $(this).slideDown('slow', function () {
        $(this).addClass('selected');
        divs.not(this).removeClass('selected');
    });
}

性能取决于很多东西（firebug 打开、div 的内容、div 的样式、半透明背景等） .) ——不仅仅是糟糕的 javascript。

Answer 2

流畅性或缺乏流畅性并不是代码的错。有些浏览器速度很慢。这不是 JS 可以解决的问题。

您可以缩短代码，但我认为不会有任何实质性的性能改进。

$('#details-speakers').click(function() {
    $('#home, #sessions-content, #cases-content').slideUp('slow');
    $('body').animate({scrollTop: $("#details").offset().top - 16}, 200, "swing");
  $('#speakers-content').slideDown('slow', function() {
        $('#details-speakers').addClass('selected');
        //Remove other classes
        $('#details-sessions, #details-cases, #details-workshops').removeClass('selected');
  });
});

$('#details-sessions').click(function() {
    $('#home, #speakers-content, #cases-content').slideUp('slow');
    $('body').animate({scrollTop: $("#details").offset().top - 16}, 200, "swing");
  $('#sessions-content').slideDown('slow', function() {
    $('#details-sessions').addClass('selected');
        //Remove other classes
        $('#details-speakers, #details-cases, #details-workshops').removeClass('selected');
  });
});

$('#details-cases').click(function() {
    $('#home, #speakers-content, #sessions-content').slideUp('slow');
    $('body').animate({scrollTop: $("#details").offset().top - 16}, 200, "swing");
  $('#cases-content').slideDown('slow', function() {
    $('#details-cases').addClass('selected');
        //Remove other classes
        $('#details-speakers, #details-sessions, #details-workshops').removeClass('selected');
  });
});

Answer 3

如果这是一种更干净的方法，您正在寻找这样的方法：

$(".my4Divs").click(function() {
    var self = this;
    $(".my4Divs").each(function() {
       if(self == this) {
          $(self).addClass("selected");
          ...
          ...
          return;
       }
       $(this).removeClass("selected");
       ...
       ...
    });
});