Django 管理默认过滤器

Question

我知道我已经设法做到了这一点，但不记得如何做到这一点，也找不到任何有关此的文档。.

如何在管理中的对象列表视图上默认应用过滤器？

我有一个列出报价的应用程序，这些报价有一个状态（例如：接受、拒绝、保留......）。

我希望默认情况下将过滤器设置为 status='accepted' ，即..

Answer 1

更可重用的方法：

class DefaultFilterMixIn(admin.ModelAdmin):
    def changelist_view(self, request, *args, **kwargs):
        from django.http import HttpResponseRedirect
        if self.default_filters:
            try:
                test = request.META['HTTP_REFERER'].split(request.META['PATH_INFO'])
                if test and test[-1] and not test[-1].startswith('?'):
                    url = reverse('admin:%s_%s_changelist' % (self.opts.app_label, self.opts.module_name))
                    filters = []
                    for filter in self.default_filters:
                        key = filter.split('=')[0]
                        if not request.GET.has_key(key):
                            filters.append(filter)
                    if filters:                        
                        return HttpResponseRedirect("%s?%s" % (url, "&".join(filters)))
            except: pass
        return super(DefaultFilterMixIn, self).changelist_view(request, *args, **kwargs)            

然后只需在 ModelAdmin 上定义一个 default_filters ：

class YourModelAdmin(DefaultFilterMixIn):
    ....
    default_filters = ('snapshot__exact=0',)

Answer 2

最后，这就是我正在寻找的：

def changelist_view(self, request, extra_context=None):
    if not request.GET.has_key('status__exact'):
        q = request.GET.copy()
        q['status__exact'] = '1'
        request.GET = q
        request.META['QUERY_STRING'] = request.GET.urlencode()
    return super(SoumissionAdmin,self).changelist_view(request, extra_context=extra_context)

另一种方式，使用管理类中的 queryset 方法不起作用。事实上，它确实过滤了结果，但它使过滤功能被破坏。

我找到的解决方案也不完美，当使用它来选择“全部/过滤器”时，这是不可能的。就我而言，它并不引人注目，但已经足够好了..

Answer 3

您可以覆盖查询集

class QuoteAdmin(admin.ModelAdmin):
    def get_queryset(self, request):
        return super(QuoteAdmin,self).get_queryset(request).filter(status="accepted")

，但是通过覆盖查询集，您将永远无法查看状态不为“已接受”的报价。

或者，您可以链接到以下 URL，将过滤器添加到 GET 参数。

/admin/myapp/quote/?status=accepted

Answer 4

简短而干净的解决方案。单击更改列表视图时，与“全部”选项配合良好。

    def changelist_view(self, request, extra_context=None):
        if not request.META['QUERY_STRING'] and \
            not request.META.get('HTTP_REFERER', '').startswith(request.build_absolute_uri()):
            return HttpResponseRedirect(request.path + "?status__exact=1")
        return super(YourModelAdmin,self).changelist_view(request, extra_context=extra_context)

Answer 5

我通过支持“全部”解决了这个问题。

在 models.py 中：

STATUSES_CHOICE = (
    ('0', 'Active'),
    ('1', 'Deactive'),
    ('2', 'Suspended'),
)

class Client(models.Model):
    ...
    status = models.IntegerField(verbose_name=_('Status'),
                                 default=0,
                                 db_index=True)

在 admin.py 中：

class StatusAdminFilter(SimpleListFilter):
    title = _('Status')
    parameter_name = 'status'
    all_param_value = 'all'

    def lookups(self, request, model_admin):
        return STATUSES_CHOICE

    def queryset(self, request, queryset):
        status = self.value()
        try:
            return (queryset if status == self.all_param_value else
                    queryset.filter(status=int(status)))
        except ValueError:
            raise Http404

    def choices(self, cl):
        yield {'selected': self.value() == self.all_param_value,
               'query_string': cl.get_query_string(
                   {self.parameter_name: self.all_param_value}, 
                   [self.parameter_name]),
               'display': _('All')}
        for lookup, title in self.lookup_choices:
            yield {'selected': self.value() == lookup,
                   'query_string': cl.get_query_string(
                       {self.parameter_name: lookup}, []),
                   'display': title}


class ClientAdmin(admin.ModelAdmin):
    list_filter = (StatusAdminFilter,)

    def changelist_view(self, request, extra_context=None):
        if not request.GET.has_key('status'):
            q = request.GET.copy()
            q['status'] = '0'  # default value for status
            request.GET = q
            request.META['QUERY_STRING'] = request.GET.urlencode()
        return super(ClientAdmin, self).changelist_view(
            request, extra_context=extra_context)

Answer 6

我想我已经找到了一种在不限制用户的情况下做到这一点的方法。只需查看引荐来源网址即可确定用户是否刚刚到达此页面。如果是这样，根据该过滤器将它们重定向到您想要的默认 URL。

def changelist_view(self, request, extra_context=None):
    try:
        test = request.META['HTTP_REFERER'].split(request.META['PATH_INFO'])
        if test and test[-1] and not test[-1].startswith('?') and not request.GET.has_key('status__exact'):
            return HttpResponseRedirect("/admin/app/model/?status__exact=1")
    except: pass # In case there is no referer
    return super(MyModelAdmin,self).changelist_view(request, extra_context=extra_context)

Answer 7

这对我有用，避免了 h3 提到的“全部”问题。

class MyAdmin(admin.ModelAdmin):
  def changelist_view(self, request, extra_context=None):
    referer = request.META.get('HTTP_REFERER', '')
    showall = request.META['PATH_INFO'] in referer and not request.GET.has_key('timeframe')
    if not showall and not request.GET.has_key('param_name_here'):
        q = request.GET.copy()
        q['param_name_here'] = 'default_value_here'
        request.GET = q
        request.META['QUERY_STRING'] = request.GET.urlencode()
    return super(SerializableAdmin,self).changelist_view(request, extra_context=extra_context)

Answer 8

这是我对 glic3rinu 代码的更新（请参阅那里的评论），它适用于 Python 3.4 和 Django 1.9.7：

class DefaultFilterMixIn(admin.ModelAdmin):
    def changelist_view(self, request, *args, **kwargs):
        from django.http import HttpResponseRedirect
        if self.default_filters:
            #try:
                test = request.META['HTTP_REFERER'].split(request.META['PATH_INFO'])
                if test and test[-1] and not test[-1].startswith('?'):
                    url = reverse('admin:{}_{}_changelist'.format(self.opts.app_label, self.opts.model_name))
                    filters = []
                    for filter in self.default_filters:
                        key = filter.split('=')[0]
                        if not key in request.GET:
                            filters.append(filter)
                    if filters:                     
                        return HttpResponseRedirect("{}?{}".format(url, "&".join(filters)))
            #except: pass
        return super(DefaultFilterMixIn, self).changelist_view(request, *args, **kwargs)            

Answer 9

这是我在 admin 中设置默认过滤器的尝试（仅使用 Django 1.11 进行了测试）：

class ZeroCountListFilter(admin.SimpleListFilter):
    title = _('include zero count')
    parameter_name = 'count'

    def choices(self, changelist):
        yield {
            'selected': self.value() is None or self.value() == 0,
            'query_string': changelist.get_query_string({}, [self.parameter_name]),
            'display': _('No'),
        }
        yield {
            'selected': self.value() == '1',
            'query_string': changelist.get_query_string({self.parameter_name: '1'}, []),
            'display': _("Yes"),
        }

    def lookups(self, request, model_admin):
        return (
            ('0', _('No')),
            ('1', _('Yes')),
        )

    def queryset(self, request, queryset):
        if self.value() is None or self.value() == '0':
            return queryset.exclude(count=0)
        else:
            return queryset

技巧是检查 self.value() is None 以获得默认行为