Django“视图没有返回 HttpResponse 对象。”

发布于 2024-09-06 06:44:35 字数 675 浏览 6 评论 0原文

我有一个简单的视图，在其中保存表单。代码看起来“干净”，但我无法摆脱错误：

“视图没有返回 HttpResponse 对象。”

虽然我在网上搜索过，但没有找到相关的说明。

def classroom_privacy(request,classname):
         theclass = Classroom.objects.get(classname=classname)
     if request.method == 'POST':  
       form = PrivacyClass(request.POST)
       if form.is_valid():
           new_obj = form.save(commit=False)
           new_obj.save()
           return HttpResponseRedirect('.')    
       else:
           form = PrivacyClass()     
       return render_to_response('classroom/classroom_privacy.html', {'form': form}, 
          context_instance=RequestContext(request))

原文

I have a simple view in which I'm saving a form. The code seems 'clean', but I can't get rid of the error:

"The view didn't return an HttpResponse object."

Though I've searched on the web, I did not find a relevant indication.

def classroom_privacy(request,classname):
         theclass = Classroom.objects.get(classname=classname)
     if request.method == 'POST':  
       form = PrivacyClass(request.POST)
       if form.is_valid():
           new_obj = form.save(commit=False)
           new_obj.save()
           return HttpResponseRedirect('.')    
       else:
           form = PrivacyClass()     
       return render_to_response('classroom/classroom_privacy.html', {'form': form}, 
          context_instance=RequestContext(request))

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安静被遗忘 2024-09-13 06:44:36

如果您使用Django Rest框架。使用以下代码返回HTTP 响应来解决此问题。

from django.http import HttpResponse

def TestAPI(request):
    # some logic
    return HttpResponse('Hello')

JSON响应返回示例：

def TestAPI(request):
    your_json = [{'key1': value, 'key2': value}]
    return HttpResponse(your_json, 'application/json')

有关HttpResponse的更多详细信息：
https://docs.djangoproject.com/en /3.1/ref/request-response/#django.http.HttpResponse

If you are using the Django Rest framework. Use the below code to return the HTTP response to resolve this issue.

from django.http import HttpResponse

def TestAPI(request):
    # some logic
    return HttpResponse('Hello')

JSON Response return example:

def TestAPI(request):
    your_json = [{'key1': value, 'key2': value}]
    return HttpResponse(your_json, 'application/json')

For more details about HttpResponse:
https://docs.djangoproject.com/en/3.1/ref/request-response/#django.http.HttpResponse

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咿呀咿呀哟 2024-09-13 06:44:35

验证代码的缩进

def classroom_privacy(request, classname):
    theclass = Classroom.objects.get(classname=classname)
    if request.method == 'POST':
        form = PrivacyClass(request.POST)
        if form.is_valid():
            new_obj = form.save(commit=False)
            new_obj.save()
            return HttpResponseRedirect('.') 
    else:
        form = PrivacyClass()  

    return render_to_response('classroom/classroom_privacy.html', {'form': form}, context_instance=RequestContext(request))

如果是 get 请求，则

；如果是 post 请求，则渲染未绑定的表单；如果是 post 请求，则渲染无效的表单；如果是 post 请求，则渲染绑定的表单；

如果是有效的表单，则重定向页面

verify the indentation of your code

def classroom_privacy(request, classname):
    theclass = Classroom.objects.get(classname=classname)
    if request.method == 'POST':
        form = PrivacyClass(request.POST)
        if form.is_valid():
            new_obj = form.save(commit=False)
            new_obj.save()
            return HttpResponseRedirect('.') 
    else:
        form = PrivacyClass()  

    return render_to_response('classroom/classroom_privacy.html', {'form': form}, context_instance=RequestContext(request))

if it is get request, render a unbound form

if it is post request and invalid form render a bound form

if it is post request and valid form redirect the page

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