如何在不知道键的情况下迭代字典，同时获取键和对象？
我有一个 NSDictionary 并想要迭代对象。但同时，我需要知道字典的键。
我记得有一种特殊的、奇特的快速枚举形式，但忘记了确切的语法。
有人吗？
I have an NSDictionary and want to iterate over the objects. But at the same time, I need to know the key of the dictionary.
I remember there was a special, fancy form of fast enumeration, but have forgotten the exact syntax.
Anyone?
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我认为你想要的是这样的：
取自 这里。
I think what you want is something like this:
Taken from here.
如果你喜欢积木，这也是一个不错的选择。
This is also a good choice if you like blocks.
keyEnumerator 返回一个对象，可让您迭代字典中的每个键。来自此处
keyEnumerator returns an object that lets you iterate through each of the keys in the dictionary. From here
据我所知，当您提出问题时，只有一种方法可以同时遍历键和值：
CFDictionaryApplyFunction。使用这个 Core Foundation 函数涉及到循环体的丑陋的 C 函数指针和大量同样丑陋但免费的桥接转换。
@zekel 有现代的迭代方式字典。投票给他吧！
To my knowledge, at the time when you asked the question, there was only one way of traversing keys and values at the same time:
CFDictionaryApplyFunction.Using this Core Foundation function involves an ugly C function pointer for the body of the loop and a lot of not-less-ugly, yet toll-free-bridged casting.
@zekel has the modern way of iterating a dictionary. Vote him up!