替换 vim 中第 n 次出现的单词
我看到其他问题涉及查找单词/模式的第 n 次出现，但我找不到如何在 vim 中实际替换模式的第 n 次出现。有一种明显的方法可以对所有出现的情况进行硬编码，例如
:s/.*\(word\).*\(word\).*\(word\).*/.*\1.*\2.*newWord.*/g
是否有更好的方法来做到这一点？
I saw other questions dealing with the finding the n-th occurrence of a word/pattern, but I couldn't find how you would actually substitute the n-th occurrence of a pattern in vim. There's the obvious way of hard coding all the occurrences like
:s/.*\(word\).*\(word\).*\(word\).*/.*\1.*\2.*newWord.*/g
Is there a better way of doing this?
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作为信息，
也可以替换第 42 次出现。但是，我更喜欢 给出的解决方案John Kugelman 更简单——即使它不会将自己限制在当前行。
For information,
also works to replace 42th occurrence. However, I prefer the solution given by John Kugelman which is more simple -- even if it will not limit itself to the current line.
您可以通过使用多个搜索来更简单地完成此操作。
:s/pattern/repl/命令中的空模式表示替换最新的搜索结果。然后，您可以通过执行
@:多次重复此操作，甚至可以使用10@:重复该命令 10 次。或者，如果我以交互方式执行此操作，我会执行以下操作：
这将找到从光标开始的第三次出现的单词，然后执行替换。
You can do this a little more simply by using multiple searches. The empty pattern in the
:s/pattern/repl/command means replace the most recent search result.You could then repeat this multiple times by doing
@:, or even10@:to repeat the command 10 more times.Alternatively, if I were doing this interactively I would do something like:
That would find the third occurrence of word starting at the cursor and then perform a substitution.
将一行中每第 N 次出现的 PATTERN 替换为 REPLACE。
Replace each Nth occurrence of PATTERN in a line with REPLACE.
为了替换 vim 中一行中第 n 次出现的 PATTERN，除了上面的答案之外，我只是想解释一下模式匹配，即它实际上是如何工作的，以便于理解。
我将使用的示例是替换 中第二次出现的超过 1 个空格一个句子（字符串）。
根据模式匹配代码->
根据 zs 文档，
\zs- 水平滚动文本以将光标定位在开头（左侧））
.\{-}0 个或更多，尽可能少 (*)这里。匹配任意字符和 {} 次数。
例如，这里的 ab{2,3}c 它将匹配 b 出现 2 次或 3 次的情况。
在这种情况下，我们还可以使用
.*，它是0或尽可能多的。根据 vim 非贪婪文档，“{-}”与“*”相同，但使用最短匹配优先算法。
<代码>\{N} ->匹配前一个原子的 n 个
/\<\d\{4}\>精确搜索 4 位数字，与 /\<\d\d\d\d>**忽略这些
\<\>，它们用于精确搜索，例如搜索fred ->\只会搜索 fred 而不会搜索 alfred。\( \)组合整个模式。PATTERN 这是您要匹配的模式 ->
\s\{1,}（\s - 空格和 {1,}，如上所述，搜索 1 个或多个空格）To replace the nth occurrence of PATTERN in a line in vim, in addtion to the above answer I just wanted to explain the pattern matching i.e how it is actually working for easy understanding.
The example I will be using is replacing the second occurrence of more than 1 space in a sentence(string).
According to the pattern match code->
According to the zs doc,
\zs- Scroll the text horizontally to position the cursor at the start (leftside) of the screen.
.\{-}0 or more as few as possible (*)Here . is matching any character and {} the number of times.
e.g ab{2,3}c here it will match where b comes either 2 or 3 times.
In this case, we can also use
.*which is 0 or many as many possible.According to vim non-greedy docs, "{-}" is the same as "*" but uses the shortest match first algorithm.
\{N}-> Matches n of the preceding atom/\<\d\{4}\>search for exactly 4 digits, same as /\<\d\d\d\d>**ignore these
\<\>they are for exact searching, like search for fred ->\<fred\>will only search fred not alfred.\( \)combining the whole pattern.PATTERN here is your pattern you are matching ->
\s\{1,}(\s - space and {1,} as explained just above, search for 1 or more space)这回答了您的实际问题，但没有回答您的意图。
您询问是否替换第 n 次出现的单词（但似乎意味着“在一行内”）。这是所问问题的答案，以防有人像我一样发现它 =)
对于奇怪的任务（例如需要将每 12 次出现的“狗”替换为“鹦鹉”），我喜欢使用递归录音。
首先清空 @q 中的录音
现在在 q 中开始新的录音
接下来，手动执行您想做的事情（使用上面的示例，将第 12 次出现的“dog”替换为“parrot”）：
删除“dog”并获取插入
类型 parrot
现在播放当前空的“@q”录音，
该录音不执行任何操作。
最后，停止录音：
现在 @q 中的录音将自动结束。但因为它按名称调用录音，所以它不再是空的。因此，调用录音：
它将重播录音，然后在最后，作为最后一步，再次重播。它将重复此操作直到文件末尾。
太长了；
This answers your actual question, but not your intent.
You asked about replacing the nth occurrence of a word (but seemed to mean "within a line"). Here's an answer for the question as asked, in case someone finds it like I did =)
For weird tasks (like needing to replace every 12th occurrence of "dog" with "parrot"), I like to use recursive recordings.
First blank the recording in @q
Now start a new recording in q
Next, manually do the thing you want to do (using the example above, replace the 12th occurrence of "dog" with "parrot"):
delete "dog" and get into insert
type parrot
Now play your currently empty "@q" recording
which does nothing.
Finally, stop recording:
Now your recording in @q calls itself at the end. But because it calls the recording by name, it won't be empty anymore. So, call the recording:
It will replay the recording, then at the end, as the last step, replay itself again. It will repeat this until the end of the file.
TLDR;
好吧，如果你执行
/gc那么你可以计算它要求你确认的次数，并在到达第 n 次时继续替换：DWell, if you do
/gcthen you can count the number of times it asks you for confirmation, and go ahead with the replacement when you get to the nth :D两个正则表达式按照最初的预期完成工作：
每行
%s/^\(.\{-}word\)\{3}\zs/*，或%s/\ (word\(\_.\{-}word\)\{15}\)\zs\(\_.*\)/*\3表示整个文档，后跟：%s /word\*/newword请注意，可以更改
\{3}和\{15}以获得所需的出现次数，以及匹配词。Two regex do the job as initially intended:
%s/^\(.\{-}word\)\{3}\zs/*for each line, OR%s/\(word\(\_.\{-}word\)\{15}\)\zs\(\_.*\)/*\3for whole document, followed by:%s/word\*/newwordNote that can change
\{3}and\{15}for desired occurrence number, as well as the matchword.