如何从库中初始化一个类？

发布于 2024-09-06 04:19:38 字数 619 浏览 3 评论 0原文

我在类库中有一些类（单独的程序集）。我将其引用到我的项目中，并且我想从该库中初始化一个特定的类。我只知道它的名字。所有类都实现一个接口。问题来了。

到目前为止我的代码：

using MyLibrary;
...
IMyInterface dll = Activator.CreateInstance("MyLibrary", "MyLibrary.NameOfClass") as IMyInterface;

但是 dll 始终为空。有什么想法吗？

谢谢

更新，

我删除了对库的引用并将该代码重写为：

Assembly a = Assembly.Load("MyLibrary");
Type type = a.GetType("MyLibrary.SKClass");
IMyInterface obj = Activator.CreateInstance(type) as IMyInterface;

但 obj 为空。

如果我使用 a.GetExportedTypes() 检查库类型，就会发现 SKClass 就在那里。那么为什么这段代码仍然返回 null 呢？

原文

I have a few classes in the class library (separate assembly). I referenced it to my project and I want to initialize one specific class from that library. I know only its name. All of the classes implements one interface.
And here comes the problem.

My code so far:

using MyLibrary;
...
IMyInterface dll = Activator.CreateInstance("MyLibrary", "MyLibrary.NameOfClass") as IMyInterface;

But dll is always null.
Any ideas?

Thanks

UPDATE

I remove reference to the library and rewrite that code to:

Assembly a = Assembly.Load("MyLibrary");
Type type = a.GetType("MyLibrary.SKClass");
IMyInterface obj = Activator.CreateInstance(type) as IMyInterface;

but obj is null.

If I checked library types with a.GetExportedTypes(), SKClass is there. So why is this code still returning null?

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清眉祭 2024-09-13 04:19:38

var assembly = Assembly.LoadFile(@"full\path\to.dll");

var type = assembly.GetType("Full.Namespace.Type");

var object = Activator.CreateInstance(type);

var assembly = Assembly.LoadFile(@"full\path\to.dll");

var type = assembly.GetType("Full.Namespace.Type");

var object = Activator.CreateInstance(type);

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