为什么这个简单的 bash 代码会出现语法错误？
我有以下 bash 代码，它是从“bash 食谱”（第一版）复制并粘贴的：
#!/bin/bash
VERBOSE=0;
if [[ $1 =-v ]]
then
VERBOSE=1;
shift;
fi
当我运行此代码（bash 4.0.33）时，我收到以下语法错误：
./test.sh: line 4: conditional binary operator expected
./test.sh: line 4: syntax error near `=-v'
./test.sh: line 4: `if [[ $1 =-v ]]'
这是否像 bash 中的打印错误一样简单食谱，或者是否存在版本不兼容或其他问题？最明显的解决办法是什么？我尝试过更改操作符的各种组合，但我不太熟悉 bash 脚本。
I have the following bash code, which is copied and pasted from "bash cookbook" (1st edition):
#!/bin/bash
VERBOSE=0;
if [[ $1 =-v ]]
then
VERBOSE=1;
shift;
fi
When I run this (bash 4.0.33), I get the following syntax error:
./test.sh: line 4: conditional binary operator expected
./test.sh: line 4: syntax error near `=-v'
./test.sh: line 4: `if [[ $1 =-v ]]'
Is this as simple as a misprint in the bash cookbook, or is there a version incompatibility or something else here? What would the most obvious fix be? I've tried various combinations of changing the operator, but I'm not really familiar with bash scripting.
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Bash 使用空格来标记脚本。该行：
应该是：
Bash uses spaces to tokenise scripts. The line:
should be: