创建这样的 XML 的正确方法是：

发布于 2024-09-05 19:02:12 字数 935 浏览 1 评论 0原文

我想在运行时创建这样的东西：

  <CWS>
    <Case name="10-040-00022">
      <CaseDetailsSet>
        <CaseDetail title="Patient name" /> 
        <CaseDetail title="Date of birth" /> 
      </CaseDetailsSet>
    </Case>
  </CWS>

所以我写了这样的东西（我希望在.NET中使用DOM..而不是XMLWriter等）

    XmlDocument doc = new XmlDocument();

    XmlElement root = doc.CreateElement("CWS");
    XmlElement singleCase = doc.CreateElement("Case");

    root.AppendChild(singleCase);

    singleCase.SetAttribute("name", "10-040-00022");

    XmlElement CaseDetailsSet = doc.CreateElement("CaseDetailsSet");
    singleCase.AppendChild(CaseDetailsSet);

    XmlElement CaseDetail = doc.CreateElement("CaseDetail");
    CaseDetailsSet.AppendChild(CaseDetail);
    CaseDetail.SetAttribute("title", "Patient Name");

请看一下它并告诉我我是否有问题，请考虑我编写的用于创建上述结构的代码。

非常感谢。

原文

I want to create something like this at run-time:

  <CWS>
    <Case name="10-040-00022">
      <CaseDetailsSet>
        <CaseDetail title="Patient name" /> 
        <CaseDetail title="Date of birth" /> 
      </CaseDetailsSet>
    </Case>
  </CWS>

so I wrote something like this ( I wish to use DOM in .NET .. not the XMLWriter,etc)

    XmlDocument doc = new XmlDocument();

    XmlElement root = doc.CreateElement("CWS");
    XmlElement singleCase = doc.CreateElement("Case");

    root.AppendChild(singleCase);

    singleCase.SetAttribute("name", "10-040-00022");

    XmlElement CaseDetailsSet = doc.CreateElement("CaseDetailsSet");
    singleCase.AppendChild(CaseDetailsSet);

    XmlElement CaseDetail = doc.CreateElement("CaseDetail");
    CaseDetailsSet.AppendChild(CaseDetail);
    CaseDetail.SetAttribute("title", "Patient Name");

please have a look at it and tell me if I am oing something wrong , regardign the code I worte to create that structure above.

much appreciated.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

殊姿 2024-09-12 19:02:12

有两件事：

您需要将根附加到 XmlDocument。

您需要添加第二个 CaseDetail。

XmlDocument doc = new XmlDocument();

XmlElement root = doc.CreateElement("CWS");

doc.AppendChild(根); // 将根元素追加到 XmlDocument

XmlElement singleCase = doc.CreateElement("Case");

root.AppendChild(singleCase);

singleCase.SetAttribute("名称", "10-040-00022");

XmlElement CaseDetailsSet = doc.CreateElement("CaseDetailsSet");
singleCase.AppendChild(CaseDetailsSet);

XmlElement CaseDetail = doc.CreateElement("CaseDetail");
CaseDetailsSet.AppendChild(CaseDetail);
CaseDetail.SetAttribute("标题", "患者姓名");

// 添加第二个案例详细信息
XmlElement CaseDetailDateOfBirth = doc.CreateElement("CaseDetail");
CaseDetailsSet.AppendChild(CaseDetailDateOfBirth);
CaseDetailDateOfBirth.SetAttribute("头衔", "出生日期");

Two things:

You'll need to append the root to the XmlDocument.

You need to add the second CaseDetail.

XmlDocument doc = new XmlDocument();

XmlElement root = doc.CreateElement("CWS");

doc.AppendChild(root); // Append the root element to the XmlDocument

XmlElement singleCase = doc.CreateElement("Case");

root.AppendChild(singleCase);

singleCase.SetAttribute("name", "10-040-00022");

XmlElement CaseDetailsSet = doc.CreateElement("CaseDetailsSet");
singleCase.AppendChild(CaseDetailsSet);

XmlElement CaseDetail = doc.CreateElement("CaseDetail");
CaseDetailsSet.AppendChild(CaseDetail);
CaseDetail.SetAttribute("title", "Patient Name");

// add the second case detail
XmlElement CaseDetailDateOfBirth = doc.CreateElement("CaseDetail");
CaseDetailsSet.AppendChild(CaseDetailDateOfBirth);
CaseDetailDateOfBirth.SetAttribute("title", "Date of birth");

回复收藏 0 原文

送君千里 2024-09-12 19:02:12

只是想展示如何使用 Linq-to-XML 来做到这一点

XElement doc = new XElement("CWS",
    new XElement("Case",
        new XAttribute("name", "10-040-00022"),
        new XElement("CaseDetailSet",
            new XElement("CaseDetail",
                new XAttribute("title", "Patient name")),
            new XElement("CaseDetail",
                new XAttribute("title", "Date of birth")))));

Just thought I'd show how to do this with Linq-to-XML

XElement doc = new XElement("CWS",
    new XElement("Case",
        new XAttribute("name", "10-040-00022"),
        new XElement("CaseDetailSet",
            new XElement("CaseDetail",
                new XAttribute("title", "Patient name")),
            new XElement("CaseDetail",
                new XAttribute("title", "Date of birth")))));

回复收藏 0 原文