Drupal Form 无法访问 javascript 函数（错误“不是函数”）
使用 drupal 和 lightbox2 打开表单。该表单来自自定义模块。
该模块有一个设置： 'onsubmit' => '返回表单提交（此）；'这似乎工作正常。
我已将functions.js 包含在theme.info 文件中并且它已显示，我可以打开该文件并查看该函数。
由于某种原因，当我提交表单时，我不断收到“form_submission not a function”。
if(Drupal.jsEnabled)
{
$(document).ready(function() {
// Call back function for AJAX call
var form_submission = function(responseText) {
alert (responseText);
}
// preventing entire page from reloading
return false;
});
}
using drupal with lightbox2 to open a form. this form is from a custom module.
the module has a setting: 'onsubmit' => 'return form_submission(this);' and that appears to be working correctly.
I've included the functions.js in the theme.info file and it's showing up, i can open that file and see the function.
for some reason, i keep getting "form_submission not a function" when i do submit the form.
if(Drupal.jsEnabled)
{
$(document).ready(function() {
// Call back function for AJAX call
var form_submission = function(responseText) {
alert (responseText);
}
// preventing entire page from reloading
return false;
});
}
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您的 form_submission 函数是其内部匿名函数的本地函数（即文档准备函数）。
您需要在文档之外的全局范围内声明该函数。您至少需要声明变量 form_submission。然后您就可以将该功能附加到您想要的任何位置。
Your form_submission function is local to the anonymous function it's inside (ie the document ready function).
You need to declare the function in a global scope, outside of the document ready. You at least need to declare the variable form_submission. You will then be able to attach the function on to it wherever you wish.
form_submission 必须是一个已定义的函数。
或者也尝试
form_submission has to be a defined function.
or also try
这并不是一个完美的答案，但我从 document.ready jquery 包装器中删除了该函数，并且它接受了它。
Not that this is the perfect answer, but I removed the function from within the document.ready jquery wrapper and it picked up on it.