如何通过cstdlib系统传递带空格的参数
我有这个 Windows 控制台应用程序，它接受一个文件，进行一些计算，然后将输出写入指定的文件。输入以“app.exe -input fullfilename”格式指定。我需要从我的 C++ 程序调用此应用程序，但文件路径中存在空格问题。当我通过键入直接从 cmd.exe 调用应用程序（为了清楚起见，没有指定输出文件）时，
"c:\first path\app.exe" -input "c:\second path\input.file"
一切都按预期工作。但是，当我尝试使用 cstdlib std::system() 函数时，即
std::system(" \"c:\\first path\\app.exe\" -input \"c:\\second path\\input.file\" ");
控制台打印出 c:\first 不是任何有效命令。这可能是常见的错误，并且有简单的解决方案，但我一直找不到任何解决方案。感谢您的帮助。
I have this windows console app which takes a file, do some calculations, and then writes the output to a specified file. The input is specified in "app.exe -input fullfilename" format. I need to call this application from my C++ program, but I have a problem with spaces in paths to files. When I call the app directly from cmd.exe by typing (without specifying output file for clarity)
"c:\first path\app.exe" -input "c:\second path\input.file"
everything works as expected. But, when I try using cstdlib std::system() function, i.e.
std::system(" \"c:\\first path\\app.exe\" -input \"c:\\second path\\input.file\" ");
the console prints out that c:\first is not any valid command. It's probably common mistake and has simple solution, but I have been unable to find any. Thx for any help.
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您应该使用 Windows API 中的 _wspawnv 函数，而不是 std::system()。如果您想在 PATH 中搜索程序，而不是指定它的完整路径，请使用 _wspawnvp。
#include <stdio.h> #include <wchar.h> ... const WCHAR *app = L"C:\\path to\\first app.exe"; const WCHAR *argv[] = {app, L"-input", L"c:\\second path\\input file.txt"}; _wpspawnv(_P_WAIT, app, argv);如果您 100% 确定您的输入文件名永远不会包含 ASCII 以外的任何内容，您也可以使用 _spawnv / _spawnvp。
Instead of std::system(), you should use the _wspawnv function from the Windows API. Use _wspawnvp if you want to search for the program in PATH, rather than specifying a full path to it.
#include <stdio.h> #include <wchar.h> ... const WCHAR *app = L"C:\\path to\\first app.exe"; const WCHAR *argv[] = {app, L"-input", L"c:\\second path\\input file.txt"}; _wpspawnv(_P_WAIT, app, argv);You could also use _spawnv / _spawnvp if you are 100% sure that your input filename will never, ever contain anything else than ASCII.
不要尝试在 std::system() 调用中添加引号。请尝试以下操作：
Don't try to put the quotes in the std::system() call. Try the following: