JAVA：将输入存储到数组中
我需要编写一个程序，该程序将生成随机字母，并且我需要将这个随机字符存储到数组中，
char[] arrayRandom = new char[10];
for (int i = 0; i < 8; i++) {
randomNumLet = (generator.nextInt(20) + 1);
System.out.print(arrayRandomLetter[randomNumLet] + " ");
arrayRandomLetter[randomNumLet] = arrayRandom[i];
}
我的代码有什么问题吗？ 因为当我运行它并打印数组时，我得到数组中所有值的框，并且有一些字母这行代码无法打印
System.out.print(arrayRandomLetter[randomNumLet] + " ");
谢谢
I need to write a program where the program would generate random letter and i would need to store this random character into an array
char[] arrayRandom = new char[10];
for (int i = 0; i < 8; i++) {
randomNumLet = (generator.nextInt(20) + 1);
System.out.print(arrayRandomLetter[randomNumLet] + " ");
arrayRandomLetter[randomNumLet] = arrayRandom[i];
}
is there anything wrong with my code?
because when i run this and printed the array i get boxes for all the values in the array and there are some letter that this line of code cannot print
System.out.print(arrayRandomLetter[randomNumLet] + " ");
Thanks
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您正在为
arrayRandomLetter的元素分配arrayRandom中的值。由于您从未初始化arrayRandom，因此它的值都是 0。0 不是可打印字符的值，因此是方框。选择随机字符的一个简单方法如下：
You're assigning an element of
arrayRandomLettera value fromarrayRandom. As you never initializearrayRandom, its values are all 0. 0 is not the value of a printable character, hence the boxes.An easy way to pick a random character is like this:
您正在尝试在分配 arrayRandomLetter 之前打印它。
You are trying to print
arrayRandomLetterbefore it is assigned.我不会给你答案，但我会给你一个提示：
@fastcodejava 的答案解释了为什么你会看到“盒子”——渲染 ASCII NUL 字符。
@Mark Peters 也是正确的，但这不是最简单的解决方案。
I'm not going to give you the answer, but I will give you a hint:
@fastcodejava's answer explains why you are seeing "boxes" -- rendering the ASCII NUL character.
@Mark Peters is also correct, but that's not the simplest solution.