从 matplotlib 中给定的颜色图创建颜色生成器

发布于 2024-09-05 07:25:56 字数 601 浏览 3 评论 0原文

我有一系列线条，每条线条都需要用单独的颜色绘制。每条线实际上由多个数据集（正区域、负区域等）组成，因此我希望能够创建一个生成器，在整个光谱中一次提供一种颜色，例如 gist_rainbow 地图此处显示。

我找到了以下作品，但看起来很复杂，更重要的是很难记住，

from pylab import *

NUM_COLORS = 22

mp = cm.datad['gist_rainbow']
get_color = matplotlib.colors.LinearSegmentedColormap.from_list(mp, colors=['r', 'b'], N=NUM_COLORS)
...
# Then in a for loop
    this_color = get_color(float(i)/NUM_COLORS)

而且它没有涵盖 gist_rainbow 地图中的颜色范围，我必须重新定义地图。

也许生成器不是最好的方法，如果是的话，可接受的方法是什么？

原文

I have a series of lines that each need to be plotted with a separate colour. Each line is actually made up of several data sets (positive, negative regions etc.) and so I'd like to be able to create a generator that will feed one colour at a time across a spectrum, for example the gist_rainbow map shown here.

I have found the following works but it seems very complicated and more importantly difficult to remember,

from pylab import *

NUM_COLORS = 22

mp = cm.datad['gist_rainbow']
get_color = matplotlib.colors.LinearSegmentedColormap.from_list(mp, colors=['r', 'b'], N=NUM_COLORS)
...
# Then in a for loop
    this_color = get_color(float(i)/NUM_COLORS)

Moreover, it does not cover the range of colours in the gist_rainbow map, I have to redefine a map.

Maybe a generator is not the best way to do this, if so what is the accepted way?

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偷得浮生 2024-09-12 07:25:56

要从特定颜色图中索引颜色，您可以使用：

import pylab
NUM_COLORS = 22

cm = pylab.get_cmap('gist_rainbow')
for i in range(NUM_COLORS):
    color = cm(1.*i/NUM_COLORS)  # color will now be an RGBA tuple

# or if you really want a generator:
cgen = (cm(1.*i/NUM_COLORS) for i in range(NUM_COLORS))

To index colors from a specific colormap you can use:

import pylab
NUM_COLORS = 22

cm = pylab.get_cmap('gist_rainbow')
for i in range(NUM_COLORS):
    color = cm(1.*i/NUM_COLORS)  # color will now be an RGBA tuple

# or if you really want a generator:
cgen = (cm(1.*i/NUM_COLORS) for i in range(NUM_COLORS))

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