Zend 框架控制器动作助手

Question

添加操作助手类后出现致命错误。我正在尝试加载与调用的布局相对应的布局。以下是我的代码片段：

首先，我在 application/controller/helpers 下添加了一个帮助器类：

class Zend_Controller_Action_Helper_Layout extends Zend_Controller_Action_Helper_Abstract {

public $pluginLoader;


public function __construct() 
{
    // TODO Auto-generated Constructor
    $this->pluginLoader = new Zend_Loader_PluginLoader ();
}


public function preDispatch()
{
        $bootstrap = $this->getActionController()->getInvokeArg('bootstrap');
        $config = $bootstrap->getOptions();
        $module = $this->getRequest()->getModuleName();
        if (isset($config[$module]['resources']['layout']['layout'])) {
            $layoutScript = $config[$module]['resources']['layout']['layout'];
            $this->getActionController()->getHelper('layout')->setLayout($layoutScript);
        }

    }

}

然后我在 bootstrap.php 中添加了一个加载器：

protected function _initLayoutHelper() {

    $this->bootstrap('frontController');
    Zend_Controller_Action_HelperBroker::addPath(APPLICATION_PATH .'/controllers/helpers');

    $layout = Zend_Controller_Action_HelperBroker::addHelper(new Zend_Controller_Action_Helper_Layout());
}

以下是我的 application.ini：

[production]
autoloaderNamespaces.tree = "Tree_"
phpSettings.display_startup_errors = 0
phpSettings.display_errors = 0
includePaths.library = APPLICATION_PATH "/../library"
bootstrap.path = APPLICATION_PATH "/Bootstrap.php"
bootstrap.class = "Bootstrap"
resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers"
resources.frontController.moduleDirectory = APPLICATION_PATH "/modules"
resources.frontController.helperDirectory = APPLICATION_PATH "/controllers/helpers"

resources.modules[] = ""
contact.resources.frontController.defaultControllerName = "index"
resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts"
resources.layout.layout = layout
admin.resources.layout.layout = admin
#admin.resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts"

resources.view[] =

[staging : production]

[testing : production]
phpSettings.display_startup_errors = 1
phpSettings.display_errors = 1

[development : production]
phpSettings.display_startup_errors = 1
phpSettings.display_errors = 1

运行此代码时，我收到以下错误：

警告： 包括（Zend\Controller\Action\Helper\LayoutLoader.php） [function.include]：打开失败 流：没有这样的文件或目录 D:\个人\proj\renovate\library\Zend\Loader.php 第83行

警告：include() [函数.include]： 打开失败 'Zend\Controller\Action\Helper\LayoutLoader.php' 纳入 (include_path='D:\personal\proj\renovate\application/../library;D:\personal\proj\renovate\library;.;C:\php5\pear') 在 D:\个人\proj\renovate\library\Zend\Loader.php 第83行

致命错误：类 'Zend_Controller_Action_Helper_LayoutLoader' 未找到于 D:\个人\proj\renovate\application\Bootstrap.php 第 33 行

，请告诉我，我该如何解决这个问题。我是 Zend 框架的初学者。

Answer 1

似乎您的 include_path 无效

请尝试将其插入到 index.php 中：

define('ROOTDIR', dirname(__FILE__) . DIRECTORY_SEPARATOR);
define('LIBDIR', realpath(ROOTDIR . '../library') . DIRECTORY_SEPARATOR);
set_include_path(implode(PATH_SEPARATOR, array_merge(explode(PATH_SEPARATOR,ini_get('include_path')), array(LIBDIR))));

这适用于如下目录结构：

application/
library/
- Zend/
httpdocs/
- index.php

Answer 2

我认为包含路径是有效的。以下是我的index.php

定义应用程序目录的路径

defined('APPLICATION_PATH') || define('APPLICATION_PATH', realpath(dirname(__FILE__) . '/../application'));

定义应用程序环境

defined('APPLICATION_ENV') || define('APPLICATION_ENV', (getenv('APPLICATION_ENV') ? getenv('APPLICATION_ENV') : 'development'));

确保library/位于include_path上

set_include_path(implode(PATH_SEPARATOR, array(realpath(APPLICATION_PATH . '/../library'),get_include_path(),)));

/** Zend_Application */
require_once 'Zend/Application.php'; 

// Create application, bootstrap, and run
$application = new Zend_Application(APPLICATION_ENV, APPLICATION_PATH . '/configs/application.ini');
$application->bootstrap()->run();