BackgroundWorker 和 Progressbar.Show()

发布于 2024-09-04 16:09:23 字数 481 浏览 6 评论 0 原文

我正在使用 Visual Studio 2010 和 C#，并尝试显示进度条，但它不起作用。

我听一个事件。如果发生这种情况，我想做一些工作并在执行此操作时显示进度条。

这就是我所做的：

static void Main(string[] args) {
  ProgressForm form = new ProgressForm();
  new FileWatcher(form).Start();
  Application.Run();
}

ProgressForm:
bgWorker.DoWork += new DoWorkEventHandler(bgWorker_DoWork);
private void bgWorker_DoWork(object sender, DoWorkEventArgs e) {
  this.Show();
  ....
}

但没有任何显示。为什么这不起作用？

谢谢再见尤尔根

原文

I am using Visual Studio 2010 and C# and try to get my progressbar to show but it doesn't work.

I listen to an event. If it happens I want to do some work and show a progressbar while doing that.

This is what I do:

static void Main(string[] args) {
  ProgressForm form = new ProgressForm();
  new FileWatcher(form).Start();
  Application.Run();
}

ProgressForm:
bgWorker.DoWork += new DoWorkEventHandler(bgWorker_DoWork);
private void bgWorker_DoWork(object sender, DoWorkEventArgs e) {
  this.Show();
  ....
}

but nothing shows. Why isn't that working?

thanks
bye juergen

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寄居人 2024-09-11 16:09:23

您不应更改 UI 表单后台线程。这应该只能从主线程完成。您可以在启动后台工作程序之前显示基本进度条，并将其隐藏在后台工作程序 RunWorkerCompleted 事件处理程序中。要报告真正的进展，您需要按照 Giorgi 的建议进行实施。

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羁客 2024-09-11 16:09:23

您无法使用 BGW 来显示表单，线程没有正确的状态。您必须使用 Thread，以便可以调用其 SetApartmentState() 方法将其切换到 STA。您还需要线程上的消息循环来保持表单处于活动状态，这需要调用 Application.Run()。并且表单必须在该线程上创建。因此：

        var t = new Thread(() => Application.Run(new Form1()));
        t.SetApartmentState(ApartmentState.STA);
        t.Start();

这种窗体的一个大问题是它不能被 UI 线程上的任何窗口所拥有。让它有消失在另一个应用程序窗口后面的趋势。此外，您的 UI 线程仍然处于死状态，几秒钟后，其窗口将在标题栏中显示“未响应”消息。

正确的方法是相反：在另一个线程上运行耗时的代码，BGW 将是一个非常好的选择。 UI 线程应该显示您的进度表。 BackgroundWorker.ReportProgress 非常适合保持进度条更新。

You cannot use a BGW to display a form, the thread does not have the proper state. You'll have to use a Thread so you can call its SetApartmentState() method to switch it to STA. You also need a message loop on the thread to keep the form alive, that requires a call to Application.Run(). And the form must be created on that thread. Thus:

        var t = new Thread(() => Application.Run(new Form1()));
        t.SetApartmentState(ApartmentState.STA);
        t.Start();

One big issue with this form is that it cannot be owned by any window on your UI thread. Giving it the tendency to disappear behind the window of another application. Also, your UI thread is still dead, its windows will ghost with the "Not Responding" message in their caption bar after a few seconds.

The proper way to do this is the other way around: run the time-consuming code on another thread, a BGW would be a very good choice. The UI thread should display your progress form. BackgroundWorker.ReportProgress is ideal to keep the progress bar updated.

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