致命错误：函数名称必须是.. PHP错误中的字符串
您好，我有一个名为 User 的类和一个名为 insertUser() 的方法。
function insertUser($first_name, $last_name, $user_name, $password, $email_address, $group_house_id)
{
$first_name = mysql_real_escape_string($first_name);
$last_name = mysql_real_escape_string($last_name);
$user_name = mysql_real_escape_string($user_name);
$password = mysql_real_escape_string($password);
$email_address = mysql_real_escape_string($email_address);
$query = "INSERT INTO Users
(FirstName,LastName,UserName,Password,EmailAddress, GroupHouseID) VALUES
('$first_name','$last_name','$user_name','$password','$email_address','$group_house_id')";
$mysql_query($query);
}
我这样称呼它：
$newUser = new User();
$newUser->insertUser($first_name, $last_name, $user_name, $email, $password, $group_house_id);
当我运行代码时，我收到此错误：
Fatal error: Function name must be a string in /Library/WebServer/Documents/ORIOnline/includes/class_lib.php on line 33
有人知道我在做什么吗？另外，这是我第一次尝试 OO PHP。
干杯，
琼斯
Hi I have a class called User and a method called insertUser().
function insertUser($first_name, $last_name, $user_name, $password, $email_address, $group_house_id)
{
$first_name = mysql_real_escape_string($first_name);
$last_name = mysql_real_escape_string($last_name);
$user_name = mysql_real_escape_string($user_name);
$password = mysql_real_escape_string($password);
$email_address = mysql_real_escape_string($email_address);
$query = "INSERT INTO Users
(FirstName,LastName,UserName,Password,EmailAddress, GroupHouseID) VALUES
('$first_name','$last_name','$user_name','$password','$email_address','$group_house_id')";
$mysql_query($query);
}
And I call it like this:
$newUser = new User();
$newUser->insertUser($first_name, $last_name, $user_name, $email, $password, $group_house_id);
When I run the code I get this error:
Fatal error: Function name must be a string in /Library/WebServer/Documents/ORIOnline/includes/class_lib.php on line 33
Anyone know what I am doing wronly? Also, this is my first attempt at OO PHP.
Cheers,
Jonesy
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$mysql_query($query);=>mysql_query($query);。请注意缺少的美元。如果您尝试对变量使用函数调用语法，它会查找名称由变量值指定的函数。在这种情况下，您没有mysql_query变量，因此它什么也没有返回，这不是一个字符串，从而给您带来错误。$mysql_query($query);=>mysql_query($query);. Note the missing dollar. If you try to use function call syntax on a variable, it looks for a function with the name given by the value of the variable. In this case, you don't have amysql_queryvariable, so it comes back with nothing, which isn't a string, and thus gives you the error.您在 mysql_query 上有一个杂散的
$。删除它：You have a stray
$on mysql_query. Remove it:对于下一个新手，如何触发/解决此错误
“PHP Fatal error: Function name must be a string in ...”
的另一个示例如下；
假设你有一个关联数组；
解决方案：
Just for the next newbie, another example of how this error
" PHP Fatal error: Function name must be a string in ..."
is triggered / and solved is as below;
Say you have an associative array;
Solution: