CakePHP 3 级深度模型关联

Question

我对 CakePHP 比较陌生，我对文档做得很好，但几周来我一直在试图找到解决这个问题的方法，但我似乎没有找到解决方案，我确信这很容易，也许甚至自动可行，但我只是不知道如何找到它（也许我不知道这类事情的行话）

我的模型结构是这样的：

<?php
    class Trip extends AppModel {
          var $belongsTo = array(
            'User' => array(
                'className' => 'User',
                'foreignKey' => 'user_id'
            ),
            'Start' => array(
                'className' => 'Place',
                'foreignKey' => 'start_id'
            ),
            'End' => array(
                'className' => 'Place',
                'foreignKey' => 'end_id'
            ),
            'Transport' => array(
                'className' => 'Transport',
                'foreignKey' => 'transport_id'
            )
        );

     }
?>

<?php
class Place extends AppModel {

    var $belongsTo = array(
        'User' => array(
            'className' => 'User',
            'foreignKey' => 'user_id'
        ),
        'Country' => array(
            'className' => 'Country',
            'foreignKey' => 'country_id'
        ),
        'State' => array(
            'className' => 'State',
            'foreignKey' => 'state_id'
        ),
        'City' => array(
            'className' => 'City',
            'foreignKey' => 'city_id'
        )
    );
    var $hasMany = array(
        'PlaceStart' => array(
            'className' => 'trip',
            'foreignKey' => 'start_id',
            'dependent' => false
        ),
        'PlaceEnd' => array(
            'className' => 'trip',
            'foreignKey' => 'end_id',
            'dependent' => false
        )
    );

}
?>

<?php
class State extends AppModel {

    var $belongsTo = array(
        'Country' => array(
            'className' => 'Country',
            'foreignKey' => 'country_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        )
    );

    var $hasMany = array(
        'City' => array(
            'className' => 'City',
            'foreignKey' => 'city_id',
            'dependent' => false
        )
    );

}
?>

......等等用户，城市，国家，和运输模型。

我想要实现的是当我搜索 Trip 时获取整个树的所有信息。

<?php
class TripController extends AppController {
    function index() {
        debug($this->Trip->find('first'));
    }
}

输出

Array
(
    [Trip] => Array
        (
            [id] => 6
            [created] => 2010-05-04 00:23:59
            [user_id] => 4
            [start_id] => 2
            [end_id] => 1
            [title] => My trip
            [transport_id] => 1
        )

    [User] => Array
        (
            [id] => 4
            [name] => John Doe
            [email] => [email protected]
        )

    [Start] => Array
        (
            [id] => 2
            [user_id] => 4
            [country_id] => 1
            [state_id] => 1
            [city_id] => 1
            [direccion] => Lincoln Street
        )

    [End] => Array
        (
            [id] => 1
            [user_id] => 4
            [country_id] => 1
            [state_id] => 1
            [city_id] => 4
            [address] => Fifth Avenue
        )

    [Transport] => Array
        (
            [id] => 1
            [name] => car
        )
)

这是问题： 如何在一次查询中获取树中的所有信息？

我想要类似

Array
(
    [Trip] => Array
        (
            [id] => 6
            [created] => 2010-05-04 00:23:59
            [User] => Array
                (
                    [id] => 4
                    [name] => John Doe
                    [email] => [email protected]
                )
            [Start] => Array
                (
                    [id] => 2
                    [user_id] => 4
                    [Country] => Array
                        (
                            [id] => 1
                            [name] = Spain
                        )
                    [State] => Array
                        (
                            [id] => 1
                            [name] = Barcelona
                        )
                    [City] => Array
                        (
                            [id] => 1
                            [name] = La Floresta
                        )
                    [address] => Lincoln Street
                )
            [End] => (same as Start)
            [title] => My trip
            [Transport] => Array
                (
                    [id] => 1
                    [name] => car
                )
        )
)

CakePHP 可以创建这种数据吗？ 不仅适用于 $this->Model->find()，也适用于 $this->paginate() 例如：

    // filter by start
    if(isset($this->passedArgs['start'])) {
        //debug('isset '.$this->passedArgs['start']);
        $start = $this->passedArgs['start'];
        $this->paginate['conditions'][] = array(
            'OR' => array(
                'Start.address LIKE' => "%$start%",
                'Start.State.name LIKE' => "%$start%",
                'Start.City.name LIKE' => "%$start%",
                'Start.Country.name LIKE' => "%$start%"
            )
        );
        $this->data['Search']['start'] = $start;
    }

这似乎是一个粗糙的问题但我确信这已经被广泛完成并记录下来，我真的很感激任何帮助。

Answer 1

您似乎一切设置都正常。您所要做的就是将递归设置为 2，这将为您的数据提供一个额外的级别（假设您已正确设置所有关系）

var $recursive =2;

Answer 2

如果您需要深入超过 2 个级别，或者如果您有很多对于这个特定问题不需要的第 2 级关联，则另一种更外科手术式的解决方案特别有用，那就是 可控制行为。这是 1.2.x 文档。如果您使用的是 v1.3.x，您可以在此处找到它。