重定向 CI 问题

发布于 2024-09-04 14:58:38 字数 482 浏览 5 评论 0原文

我对 CodeIgniter 还算陌生,而且仍在学习(很多)。

所以我有一个视图,当我提交表单时,我通过动态浏览到正确的 URL 来“调用”控制器,例如 site/delete

    class Site extends Controller {

    function index(){$this->load->view('...')}

    function delete() {
        $this->site_model->delete_row();
        $this->index();
    }

    }

现在,当该操作完成(删除行)时,我正在调用 $this->index( );重定向到我的初始页面(这很好),但我的网址仍然是:​​ site/delete 。我希望我的 URL 为 ../site/index (或没有 /index)

任何帮助将不胜感激:-)。

I'm kind of new with CodeIgniter and I'm still learning (a lot).

So I have a view and when I submit a form I 'call' the controller by surfing to the right URL dynamically e.g. site/delete

    class Site extends Controller {

    function index(){$this->load->view('...')}

    function delete() {
        $this->site_model->delete_row();
        $this->index();
    }

    }

Now when that action is done (deleted the row) I'm calling $this->index(); to redirect to my initial page (which is good) but my url stays: site/delete . I want my URL to be ../site/index (or without the /index)

Any help would be appreciated :-) .

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评论(4

放我走吧 2024-09-11 14:58:38

到目前为止,我找到了解决此问题的方法:

而不是:

$this->index();

我正在使用:

redirect('site');

有人知道这是一个很好的做法吗?

So far I found something to solve this:

instead of:

$this->index();

I'm using:

redirect('site');

Does anyone know this is a good practice?

抱猫软卧 2024-09-11 14:58:38

重定向是您应该使用的。

在用户指南中:
http://codeigniter.com/user_guide/helpers/url_helper.html

他们使用它检查用户是否登录后。根据用户是否登录,他们重定向到不同的位置。

另请注意,重定向后的任何代码都不会运行。完成所需的所有操作后,请确保并重定向。

Redirect is what you should use.

In the user guide:
http://codeigniter.com/user_guide/helpers/url_helper.html

they use it after checking if a user is logged in. Depending on if they are or not, they redirect to a different place.

Also, note that any code after the redirect won't run. Make sure and redirect after you've done everything you need to.

情泪▽动烟 2024-09-11 14:58:38

我的首选方法是使用相同的方法处理类似的操作,用户随后会看到这些操作。

如果您之后以用户身份访问 /site/delete 会怎样?它将必须检测并抛出错误(显示消息)或重定向到适当的页面。 /site/delete 没有任何意义。

例如,如果用户在删除后通常会看到概述,那么我的表单将发布到 /site/index;在执行正常工作之前,使用 index 快速检查条件并在同一控制器中调用 _delete()

这样,如果用户刷新页面或按“后退”,事情看起来应该是一致的。

另一个例子是 /settings/edit 会向自身发布 - 这意味着它可以对帖子进行操作并显示任何输出(例如验证错误)。这意味着我的网站上没有 /settings/do_edit 位置,也意味着用户可以安全地返回 /settings/edit,并查看用于编辑其内容的表单设置。

我认为这是对一个可能客观的问题的主观看法,我会鼓励大家就我的观点提供反馈,但这是我避免您所问问题的方式。

My preferred method is to have actions like that handled by the same method that will be seen by the user afterwards.

What if you go to /site/delete afterwards, as a user? It will either have to detect and throw a error (show a message) or redirect to an appropriate page. /site/delete has no meaning.

For example, if a user would normally see an overview after deleting, then my form will be posted to /site/index; with index quickly checking for the condition and calling _delete() in the same controller, before doing its normal work.

That way, if the user refreshes the page, or presses 'back', things should look consistent to them.

Another example would be that /settings/edit would post to itself - this means that it can act on the post and show any output (e.g. validation errors). It means there's no /settings/do_edit location on my site, and also means that the user can go back to /settings/edit safely, and see a form for editing their settings.

I suppose this is a subjective take on a perhaps objective question, and I would encourage feedback on my view, but it's my way of avoiding the problem you have asked about.

ζ澈沫 2024-09-11 14:58:38
$this->index();

函数中的函数调用只是执行该函数内的功能。
并且网址从未改变。

要更改您应该使用的网址。

redirect ( base_url().'site');

但你应该在构造函数中加载 url 帮助器。

$this->index();

Call of function in a function simply execute the functionality within that function.
And url never changed.

for changing the url you should use.

redirect ( base_url().'site');

but you should load url helper in constructor.

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