我如何在 jBPM 中表示并发操作,其中任何操作都可以结束流程?

发布于 2024-09-04 11:38:30 字数 705 浏览 2 评论 0原文

举个例子:许可证必须由两名律师和一名工程师审查。如果这三个中的任何一个拒绝它,则该过程进入“拒绝”结束状态。如果三者都授予许可,则进入“授予”最终状态。所有三名审查员可以同时进行审查,也可以按任意顺序进行审查。

一旦一位工程师授予了它,它就不应该可供工程师检查;一旦两名律师审查完毕,就不应该再提供给律师;一旦一名工程师和两名律师检查完毕,它应该进入既定的最终状态。

我最初的想法是,要么我有一个过于复杂的状态转换图,“相同的”中间状态多次重复,要么我携带(外部)状态与过程{boolrejected; int 工程师SignoffId; int Lawr1SignoffId; int Lawr2SignoffId}。

或者类似的东西?如果是这样,工程师的拒绝如何终止“律师”中的子流程?

START->FORK->Engineer->Granted?---------------->Y->JOIN-->Granted
          |->Lawyers-->Granted?->by 2 lawyers?->Y---^
                  ^                          |
                  |--------------------------N 

jBPM 对此问题的标准答案是什么?您能给我指出此类答案的示例或文档吗?

谢谢。

An example: a permit must be examined by two lawyers and one engineer. If any of those three reject it, the process enters a "rejected" end state. If all three grant the permit, it enters a "granted" end state. All three examiners may examine simultaneously, or in any order.

Once one engineer has granted it, it shouldn't be available to be examined by an engineer; once two lawyers have examined it, it shouldn't be available to lawyers; once one engineer and two lawyers have examined it should go to the granted end state.

My initial thinking is that either I have a overly complicated state transition diagram, with "the same" intermediate states multiply repeated, or I carry (external) state with the process { bool rejected; int engineerSignoffId; int lawyer1SignoffId; int lawyer2SignoffId}.

Or something like this? If so, how does the engineer's rejection terminate the subprocess that is in "Lawyers"?

START->FORK->Engineer->Granted?---------------->Y->JOIN-->Granted
          |->Lawyers-->Granted?->by 2 lawyers?->Y---^
                  ^                          |
                  |--------------------------N 

What's the canonical jBPM answer to this? Can you point me to examples or documentation of such answers?

Thanks.

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匿名的好友 2024-09-11 11:38:30

好吧,我不确定我是否正确理解了您的用例,但让我尝试一下。

被拒绝的最终状态很简单——你可以有很多,也可以有一个,这并不重要。如果进程达到结束状态,则进程结束。拒绝了。故事结束:
http://docs.jboss.com/jbpm/v4/userguide/html_single/ #end

现在,创建三个人工任务以供验收。一名应分配到工程师候选组,另外两名应分配到律师候选组。一旦一个人接受了一项任务(即分配给自己),其他人就不能接受该任务。
http://docs.jboss.com/jbpm/v4/userguide/html_single/ #task

所有人工任务应在最后合并,并让一个节点等待所有并发路径才能继续。即:以正确的重数连接:
http://docs.jboss.com/jbpm/v4/userguide/html_single/ #decision

我不确定您使用的是哪个 JBPM 版本,但是如果您使用 JBPM 5,这当然在 BPMN 2.0 中也是可能的。

Well, I'm not sure if I get your use case properly but let me try.

The rejected end states are easy - you can have many of them or one, it doesn't matter. If the process hits an end state, the process ends. Rejected. End of story:
http://docs.jboss.com/jbpm/v4/userguide/html_single/#end

Now, make three human tasks for acceptance. One should be assigned to engineer candidate group and two others to lawyers candidate group. Once a person takes a task (i.e. assigns to himself) it can't be taken by anybody else.
http://docs.jboss.com/jbpm/v4/userguide/html_single/#task

All the human tasks should be then merged at the end with a node waiting for all concurrent paths in order to continue. I.e.: join with correct multiplicity:
http://docs.jboss.com/jbpm/v4/userguide/html_single/#decision

I'm not sure which JBPM version are you using but this of course is also possible in BPMN 2.0, in case you use JBPM 5.

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