PyQt4 使用小部件移动 QTableWidget 行

发布于 2024-09-04 05:11:17 字数 534 浏览 3 评论 0原文

我的 PyQt4 应用程序中有以下方法。 r2是要移动的行数，r1是应该移动的位置。澄清一下：表格中填充的是 cellWidget，而不是 widgetItem。

def move_row(self, r1, r2):
    tt = self.tableWidget
    tt.insertRow(r1)
    for c in range(tt.columnCount()):
        tt.setCellWidget(r1, c, tt.cellWidget(r2 + 1, c))
    tt.removeRow(r2 + 1) # <--- ???

如果我注释掉最后一行，它的行为将按预期进行：新行插入到位置 r1 处，其中填充有来自 r2 的小部件（现在是 r2+1），并且 r2+1 行为空。如果我什至隐藏这一行，它的表现很好，尽管这不是我想要的（我对行进行了编号，并且我不希望这个隐藏的行占据该编号）。但如果我删除该行，它最初拥有的小部件就会消失。看起来他们的所有权是在第一次放置时获得的，并且在移动后不会改变。

有什么想法吗？

原文

I have the following method in my PyQt4 app. r2 is the number of row to move, and r1 is the position where it should be moved. To clarify: the table is filled with cellWidgets, not widgetItems.

def move_row(self, r1, r2):
    tt = self.tableWidget
    tt.insertRow(r1)
    for c in range(tt.columnCount()):
        tt.setCellWidget(r1, c, tt.cellWidget(r2 + 1, c))
    tt.removeRow(r2 + 1) # <--- ???

If I comment out the last line, it behaves as expected: the new row is inserted at position r1, it is filled with widgets from r2 (now it's r2+1), and the r2+1 row is empty. If I even hide this row, it behaves well, though it is not what I want (I have the rows numbered, and I don't want this hidden row to occupy the number).
But if I remove the row, the widgets initially owned by it disappear. Looks like their ownership is taken on first placement, and is not changed after the move.

Any ideas?

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