选择查询内的 SPARQL 实体列表
在下面的 DBpedia 查询中，有没有办法将 UNION 合并为单个模式？
PREFIX prop: <http://resedia.org/ontology/>
PREFIX res: <http://resedia.org/resource/>
SELECT DISTINCT ?language ?label
WHERE {
{res:Spain prop:language ?language}
UNION
{res:France prop:language ?language}
UNION
{res:Italy prop:language ?language}
?language rdfs:label ?label .
FILTER langMatches(lang(?label), "en")
}
SPARQL 规范 提到了一些有关 RDF 集合的内容，但我没有真正理解它所描述的内容。看起来以下语法应该有效，但事实并非如此。
PREFIX prop: <http://resedia.org/ontology/>
PREFIX res: <http://resedia.org/resource/>
SELECT DISTINCT ?language ?label
WHERE {
(res:Spain res:France res:Italy) prop:language ?language
?language rdfs:label ?label .
FILTER langMatches(lang(?label), "en")
}
有没有办法在 SELECT 查询中定义像这样的 URI 列表（或“多重集”或“包”）？
In the following DBpedia query, is there a way to consolidate the UNIONs into a single pattern?
PREFIX prop: <http://resedia.org/ontology/>
PREFIX res: <http://resedia.org/resource/>
SELECT DISTINCT ?language ?label
WHERE {
{res:Spain prop:language ?language}
UNION
{res:France prop:language ?language}
UNION
{res:Italy prop:language ?language}
?language rdfs:label ?label .
FILTER langMatches(lang(?label), "en")
}
The SPARQL spec mentions something about RDF collections but I don't really understand what it's describing. It seemed like the following syntax should work, but it didn't.
PREFIX prop: <http://resedia.org/ontology/>
PREFIX res: <http://resedia.org/resource/>
SELECT DISTINCT ?language ?label
WHERE {
(res:Spain res:France res:Italy) prop:language ?language
?language rdfs:label ?label .
FILTER langMatches(lang(?label), "en")
}
Is there a way to define a list (or "multiset", or "bag") of URIs like this inside a SELECT query?
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在SPARQL 1.1中你可以做
In SPARQL 1.1 you can do
简单的回答：不。
表示“包含西班牙、法国和意大利的列表具有语言的匹配”，即列表本身具有语言。
你可以这样做：
这更短，但可能更慢。
（我感觉 SPARQL 1.1 有一个“IN”功能，但我在草稿中没有看到它）
Simple answer: no.
means 'match where a list containing Spain, France and Italy has a language', i.e. the list itself has a language.
You could do:
which is shorter, but may be slower.
(I had a feeling SPARQL 1.1 had an 'IN' feature, but I don't see it in the drafts)