asp.net mvc HttpPostedFileBase获取文件扩展名

发布于 2024-09-03 11:45:14 字数 361 浏览 7 评论 0原文

public string ContructOrganizationNameLogo(HttpPostedFileBase upload, string OrganizationName, int OrganizationID,string LangName)
    {
         var UploadedfileName = Path.GetFileName(upload.FileName);
        string type = upload.ContentType;
    }

我想获取文件的扩展名来动态生成文件的名称。我将使用一种方法来分割类型。但我可以使用 HttpPostedFileBase 对象以干净的方式获取扩展名吗？

原文

public string ContructOrganizationNameLogo(HttpPostedFileBase upload, string OrganizationName, int OrganizationID,string LangName)
    {
         var UploadedfileName = Path.GetFileName(upload.FileName);
        string type = upload.ContentType;
    }

I want to get the extension of the file to dynamically generate the name of the file.One way i will use to split the type. but can i use HttpPostedFileBase object to get the extension in the clean way?

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不美如何 2024-09-10 11:45:14

像这样：

string extension = Path.GetExtension(upload.FileName);

这将包括一个前导 .。

请注意，您不应假设扩展名是正确的。

Like this:

string extension = Path.GetExtension(upload.FileName);

This will include a leading ..

Note that the you should not assume that the extension is correct.

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笑红尘 2024-09-10 11:45:14

string extension = Path.GetExtension(formFile.FileName);
string fileName = Path.GetFileNameWithoutExtension(formFile.FileName);

fileName = Path.Combine(path, Path.GetRandomFileName() + fileName + extension);

using (FileStream fs = File.Create(Path.Combine(PathConstants.RootPath, fileName)))
{
    await formFile.CopyToAsync(fs);
}
return fileName;

string extension = Path.GetExtension(formFile.FileName);
string fileName = Path.GetFileNameWithoutExtension(formFile.FileName);

fileName = Path.Combine(path, Path.GetRandomFileName() + fileName + extension);

using (FileStream fs = File.Create(Path.Combine(PathConstants.RootPath, fileName)))
{
    await formFile.CopyToAsync(fs);
}
return fileName;

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