用于 LED 模块的 ASCII 7x5 侧送字符
我在这里查看字体文件的代码： http://www.openobject.org/opensourceurbanism/Bike_POV_Beta_4
代码如下所示
const byte font[][5] = {
{0x00,0x00,0x00,0x00,0x00}, // 0x20 32
{0x00,0x00,0x6f,0x00,0x00}, // ! 0x21 33
{0x00,0x07,0x00,0x07,0x00}, // " 0x22 34
{0x14,0x7f,0x14,0x7f,0x14}, // # 0x23 35
{0x00,0x07,0x04,0x1e,0x00}, // $ 0x24 36
{0x23,0x13,0x08,0x64,0x62}, // % 0x25 37
{0x36,0x49,0x56,0x20,0x50}, // & 0x26 38
{0x00,0x00,0x07,0x00,0x00}, // ' 0x27 39
{0x00,0x1c,0x22,0x41,0x00}, // ( 0x28 40
{0x00,0x41,0x22,0x1c,0x00}, // ) 0x29 41
{0x14,0x08,0x3e,0x08,0x14}, // * 0x2a 42
{0x08,0x08,0x3e,0x08,0x08}, // + 0x2b 43
：等等...
我对这段代码的工作原理感到非常困惑 - 有人可以向我解释一下吗？
谢谢，
马吉德
I am looking at the code for the font file here:
http://www.openobject.org/opensourceurbanism/Bike_POV_Beta_4
The code starts like this:
const byte font[][5] = {
{0x00,0x00,0x00,0x00,0x00}, // 0x20 32
{0x00,0x00,0x6f,0x00,0x00}, // ! 0x21 33
{0x00,0x07,0x00,0x07,0x00}, // " 0x22 34
{0x14,0x7f,0x14,0x7f,0x14}, // # 0x23 35
{0x00,0x07,0x04,0x1e,0x00}, // $ 0x24 36
{0x23,0x13,0x08,0x64,0x62}, // % 0x25 37
{0x36,0x49,0x56,0x20,0x50}, // & 0x26 38
{0x00,0x00,0x07,0x00,0x00}, // ' 0x27 39
{0x00,0x1c,0x22,0x41,0x00}, // ( 0x28 40
{0x00,0x41,0x22,0x1c,0x00}, // ) 0x29 41
{0x14,0x08,0x3e,0x08,0x14}, // * 0x2a 42
{0x08,0x08,0x3e,0x08,0x08}, // + 0x2b 43
and so on...
I am very confused as to how this code works - can someone explain it to me please?
Thanks,
Majd
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每个 5 字节数组 = 40 位，映射到字符网格中的 7x5 = 35 个像素（大概有 5 个未使用的位）。
当您想要显示一个字符时，您可以将该字符相应的 5 字节位图复制到适当的内存位置。例如，要显示字符
X，您可以从font['X']复制数据。Each array of 5 bytes = 40 bits which map to the 7x5 = 35 pixels in the character grid (there are 5 unused bits presumably).
When you want to display a character you copy the corresponding 5 byte bitmap for that character to the appropriate memory location. E.g. to display the character
Xyou would copy the data fromfont['X'].