在 C# 中重载复合赋值运算符的简单方法？
有没有人有一个关于如何在 C# 中重载复合赋值运算符的非常简单的示例？
Does anyone have a very simple example of how to overload the compound assignment operator in C#?
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您不能显式重载复合赋值运算符。但是，您可以重载主运算符，编译器会扩展它。
x += 1纯粹是x = x + 1的语法糖，后者就是它将被翻译成的内容。如果重载+运算符，它将被调用。MSDN 运算符重载教程
You can't explicitly overload the compound assignment operators. You can however overload the main operator and the compiler expands it.
x += 1is purely syntactic sugar forx = x + 1and the latter is what it will be translated to. If you overload the+operator it will be called.MSDN Operator Overloading Tutorial
根据 C# 规范，+= 不在可重载运算符列表中。我认为，这是因为它也是一个赋值运算符，不允许重载。但是，与此处其他答案中所述不同，“x += 1”与“x = x + 1”不相同。 C# 规范“7.17.2 复合赋值”非常清楚：
重要的部分是最后一部分：x 仅计算一次。因此，在这样的情况下：
如何表述你的陈述可以（并且确实）产生影响。但我认为，在大多数情况下，差异可以忽略不计。 （即使我刚刚遇到过一个，但事实并非如此。）
因此，问题的答案是：不能覆盖 += 运算符。对于可以通过简单的二元运算符实现意图的情况，可以覆盖 + 运算符并实现类似的目标。
According to the C# specification, += is not in the list of overloadable operators. I assume, this is because it is an assignment operator as well, which are not allowed to get overloaded. However, unlike stated in other answers here, 'x += 1' is not the same as 'x = x + 1'. The C# specification, "7.17.2 Compound assignment" is very clear about that:
The important part is the last part: x is evaluated only once. So in situations like this:
it can (and does) make a difference, how to formulate your statement. But I assume, in most situations, the difference will negligible. (Even if I just came across one, where it is not.)
The answer to the question therefore is: one cannot override the += operator. For situations, where the intention is realizable via simple binary operators, one can override the + operator and archieve a similiar goal.
您无法在 C# 中重载这些运算符。
You can't overload those operators in C#.