iPhone：在单独的文件中编写一些方法以便从任何地方访问
这是一个简单的问题， 我有几个视图控制器类，还有一些其他类。 我发现我自己在所有实现文件中创建了一些方法，它们的作用相同。
我想将我的一些方法写在一个单独的文件中， 并将此文件导入到我的视图控制器中。 因此，我将能够从当前的视图控制器运行这些方法，
如果此方法需要更改，我不需要在所有实现文件中重新编写它。
让我夏普讲一件事。我不想创建一个新对象！并实例化它。 我确实希望能够像我一样运行这个方法：[self doSomething];
请帮助理解应该如何完成此操作。
IE 我有 3 个视图控制器，每个都有以下方法：
-(void)doSomething:(id)sender{
//doing something
}
只想在一个地方定义这个 doSomething 方法， 我可以通过运行以下命令从视图控制器访问它： [自己做某事]；
是否可以？
提前致谢。
here is a quick question,
i have my couple view controllers classes, and have some other classes.
i've found my self creating some methods in all of their implementation files, which are doing the same.
i would like to write some of my methods in a seperate file,
and import this file into my view controllers.
therefore, i will be able to run those methods from my current view controller,
In case this method will require a change, i will not need to re-write it in all my implementaion files.
Let me Sharp just one thing. I do not want to create a new object! and instantiate it.
i do want to be able to run this method just like i was doing: [self doSomething];
Please help to understand how this should be done.
i.e.
i have 3 view controllers, each has the bellow method:
-(void)doSomething:(id)sender{
//doing something
}
just want to have this doSomething method defined in one place,
and i could access it from my view controllers by running:
[self doSomething];
is it possible?
Thanks in advance.
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您想通过子类化来做到这一点。首先创建一个您想要所有共享方法的类，作为 UIViewController 的子类，我们将其称为 BaseViewController。例如，您的头文件中应包含以下内容：
然后 .m 文件中包含相应的定义。
现在，当您想要创建一个具有共享方法的新 UIViewController 子类时，请使新类成为 BaseViewController 而不是 UIViewController 的子类，如下所示：
You want to do this by subclassing. First create a class where you want all your shared methods, as a subclass of UIViewController, let's call it BaseViewController. For example you'd have this in your header file:
And then the corresponding definition in your .m file.
Now when you want to create a new UIViewController subclass which has the shared methods make the new class a subclass of BaseViewController not UIViewController, like so: