我一直在尝试初始化 的映射> 使用新的 0X 标准，但我似乎无法获得正确的语法。我想制作一个包含 key:value = 1:<3,4> 的单个条目的地图
#include <initializer_list>
#include <map>
#include <vector>
using namespace std;
map<int, vector<int> > A = {1,{3,4}};
....
使用 gcc 4.4.3 时，它因以下错误而终止：
error: nomatching function for call to std::map; >,std::less,std::allocator; > > > >::map()
Edit
按照 Cogwheel 的建议并添加额外的大括号，它现在编译时带有一个警告，可以使用它来消除该警告-fno-deruce-init-list 标志。这样做有危险吗？
I've been trying to initialize a map of <ints, vector<ints> > using the new 0X standard, but I cannot seem to get the syntax correct. I'd like to make a map with a single entry with key:value = 1:<3,4>
#include <initializer_list>
#include <map>
#include <vector>
using namespace std;
map<int, vector<int> > A = {1,{3,4}};
....
It dies with the following error using gcc 4.4.3:
error: no matching function for call to std::map<int,std::vector<int,std::allocator<int> >,std::less<int>,std::allocator<std::pair<const int,std::vector<int,std::allocator<int> > > > >::map(<brace-enclosed initializer list>)
Edit
Following the suggestion by Cogwheel and adding the extra brace it now compiles with a warning that can be gotten rid of using the -fno-deduce-init-list flag. Is there any danger in doing so?
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评论（1）
正如上面的评论所提到的，
{1,{3,4}}是地图中的单个元素，其中键是1，值是{3,4}。因此，您需要的是{ {1,{3,4}} }。简化错误：
不是一个精确的错误，但还是有帮助的。
As the comment above has mentioned,
{1,{3,4}}is a single element in the map, where the key is1and the value is{3,4}. So, what you would need is{ {1,{3,4}} }.Simplifying the error:
Not a precise error, but somewhat helpful nonetheless.