python：从字典调用构造函数？
我不太确定这里的术语，所以请耐心等待......
假设我有一个像这样的构造函数调用：
machineSpecificEnvironment = Environment(
TI_C28_ROOT = 'C:/appl/ti/ccs/4.1.1/ccsv4/tools/compiler/c2000',
JSDB = 'c:/bin/jsdb/jsdb.exe',
PYTHON_PATH = 'c:/appl/python/2.6.4',
)
除了我想用提供给我的字典上的操作替换它：
keys = {'TI_C28_ROOT': 'C:/appl/ti/ccs/4.1.1/ccsv4/tools/compiler/c2000',
'JSDB': 'c:/bin/jsdb/jsdb.exe',
'PYTHON_PATH': 'c:/appl/python/2.6.4'}
machineSpecificEnvironment = Environment(
... what do I put here? it needs to be a function of "keys" ...
)
我该怎么办这？
I'm not quite sure of the terminology here so please bear with me....
Let's say I have a constructor call like this:
machineSpecificEnvironment = Environment(
TI_C28_ROOT = 'C:/appl/ti/ccs/4.1.1/ccsv4/tools/compiler/c2000',
JSDB = 'c:/bin/jsdb/jsdb.exe',
PYTHON_PATH = 'c:/appl/python/2.6.4',
)
except I would like to replace that by an operation on a dictionary provided to me:
keys = {'TI_C28_ROOT': 'C:/appl/ti/ccs/4.1.1/ccsv4/tools/compiler/c2000',
'JSDB': 'c:/bin/jsdb/jsdb.exe',
'PYTHON_PATH': 'c:/appl/python/2.6.4'}
machineSpecificEnvironment = Environment(
... what do I put here? it needs to be a function of "keys" ...
)
How can I do this?
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您可以通过 ** 符号将字典应用为参数列表
You can apply a dict as an argument list by the ** notation