这个迭代的河内塔是如何运作的? C
可能的重复:
这是如何工作的?奇怪的河内塔解决方案
在浏览 Google 时,我发现了这个有趣的河内塔解决方案,它甚至不使用堆栈作为数据结构。
谁能简单地解释一下我,它实际上在做什么?
这个解决方案真的可以接受吗?
代码
#include <stdio.h>
#include <stdlib.h>
int main()
{
int n, x;
printf("How many disks?\n");
scanf("%d", &n);
printf("\n");
for (x=1; x < (1 << n); x++)
printf("move from tower %i to tower %i.\n",
(x&x-1)%3, ((x|x-1)+1)%3);
return 0;
}
更新:硬编码的数字 3 在这里做什么?
Possible Duplicate:
How does this work? Weird Towers of Hanoi Solution
While surfing Google, i found this interesting solution to Tower Of Hanoi which doesn't even use stack as data structure.
Can anybody explain me in brief, what is it actually doing?
Are this solution really acceptable?
Code
#include <stdio.h>
#include <stdlib.h>
int main()
{
int n, x;
printf("How many disks?\n");
scanf("%d", &n);
printf("\n");
for (x=1; x < (1 << n); x++)
printf("move from tower %i to tower %i.\n",
(x&x-1)%3, ((x|x-1)+1)%3);
return 0;
}
Update: What is the hard-coded number 3 doing in here?
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在伪代码中可能更容易看出:
1 左移 n 位基本上是 2 的 n 次方,在 4 个磁盘的情况下为 16。
如果您手动执行此序列,您应该会看到圆盘移动的进度。 http://library.ust.hk/images/highlights/Tower_of_Hanoi_4.gif
Might be easier to see in PSEUDOCODE:
1 LEFT SHIFTED BY n BITS is basically 2 to the power of n, 16 in the case of 4 disks.
If you walk through this sequence manually, you should see the progression of movement of the disks. http://library.ust.hk/images/highlights/Tower_of_Hanoi_4.gif
它是汉诺塔的二进制解决方案之一,维基百科上有该算法的详细说明 - 阅读 “二元解决方案”段落。
It is one of the binary solutions to Tower of Hanoi, there is a detailed explanation of this algorithm on Wikipedia - read the "Binary solution" paragraph.