如何测试需要输入安全短语中的两个随机字符的表单？

Question

我需要测试一个两阶段登录系统，该系统首先询问您的电子邮件地址和密码，然后向用户提供两个包含 [a-zA-Z0-9] 的选择列表。下拉菜单旁边的标签采用“从安全短语中选择字符 X”的形式，其中 X 是已知安全短语中的随机字符索引。

我不想为验收测试存根代码，所以是否可以在黄瓜中编写一个匹配器，在我们知道整个短语的情况下，它可以在两个列表中的每个列表中选择所需的字符？

以下是我到目前为止所遇到的场景以及所涉及的步骤：

Scenario: valid login email, password and secret phrase takes me to the dashboard
  Given I am not logged in
  When I log in as "[email protected]"
  Then I should be on the dashboard page
  And I should see "Your Dashboard"

When /^I log in as "([^\"]*)"$/ do |login|
  visit path_to('Login page')
  fill_in "Email", :with => login
  fill_in "Password", :with => "Password123"
  click_button "Log in"
  response.should contain("Please verify some characters from your security phrase")
  select "a", :from => "Select character X of your security phrase"
  select "b", :from => "Select character Y of your security phrase"  
  click_button "Submit"
end

例如，如果安全短语是“Secret123”，X = 3 且 Y = 8，则上面的结果必须生成等价的：

select "c", :from => "Select character 3 of your security phrase"
select "2", :from => "Select character 8 of your security phrase"

中的数字 X 和 Y实际页面分别位于span#svc_1和span#svc_2内。

谢谢，

Answer 1

经过一番折腾，我终于想通了。在这里记录下来，以便可以帮助处于相同情况的其他人。在general_steps.rb中：

When /^I log in as "([^\"]*)"$/ do |email|
  visit path_to('Login page')
  fill_in "Email", :with => email
  fill_in "Password", :with => "password"
  click_button "Log in"
  response.should contain("Please verify some characters from your secret phrase")
  select_correct_secret_phrase_char("span#sec_1")
  select_correct_secret_phrase_char("span#sec_2")
  click_button "Submit"
end

def select_correct_secret_phrase_char(css_selector)
  response.should have_selector(css_selector) do |scope|
    select "Secret1"[(scope.text.to_i)-1].chr, :from => "Select character #{scope.text} of your security phrase"
  end
end