如何在 Java 中枚举压缩文件夹的内容？

发布于 2024-09-01 23:51:45 字数 255 浏览 2 评论 0原文

ZipeFile file = new ZipFile(filename);
ZipEntry folder = this.file.getEntry("some/path/in/zip/");
if (folder == null || !folder.isDirectory())
  throw new Exception();

// now, how do I enumerate the contents of the zipped folder?

原文

ZipeFile file = new ZipFile(filename);
ZipEntry folder = this.file.getEntry("some/path/in/zip/");
if (folder == null || !folder.isDirectory())
  throw new Exception();

// now, how do I enumerate the contents of the zipped folder?

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青巷忧颜 2024-09-08 23:51:45

看起来没有办法枚举某个目录下的 ZipEntry 。

您必须遍历所有 ZipFile.entries() 并根据 ZipEntry.getName() 并查看是否 String.startsWith(字符串前缀)< /代码>。

String specificPath = "some/path/in/zip/";

ZipFile zipFile = new ZipFile(file);
Enumeration<? extends ZipEntry> entries = zipFile.entries();
while (entries.hasMoreElements()) {
    ZipEntry ze = entries.nextElement();
    if (ze.getName().startsWith(specificPath)) {
        System.out.println(ze);
    }
}

It doesn't look like there's a way to enumerate ZipEntry under a certain directory.

You'd have to go through all ZipFile.entries() and filter the ones you want based on the ZipEntry.getName() and see if it String.startsWith(String prefix).

String specificPath = "some/path/in/zip/";

ZipFile zipFile = new ZipFile(file);
Enumeration<? extends ZipEntry> entries = zipFile.entries();
while (entries.hasMoreElements()) {
    ZipEntry ze = entries.nextElement();
    if (ze.getName().startsWith(specificPath)) {
        System.out.println(ze);
    }
}

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