如何对齐 C++ emacs 中的一列中的类成员名称？

发布于 2024-09-01 22:09:13 字数 541 浏览 4 评论 0原文

我想将所有 C++ 类成员名称（不要与成员类型混淆）对齐在一列中。

让我们看一下入口处的示例：

class Foo
{
public:
    void   method1( );
    int                  method2( ); 
    const Bar *        method3( ) const; 
protected:
    float    m_member;
};

这就是我们希望在结尾处看到的内容：

class Foo
{
public:
    void           method1( );
    int            method2( ); 
    const Bar *    method3( ) const; 
protected:
    float          m_member;
};

因此，最长的成员类型声明定义了类成员名称将与其对齐的列。我怎样才能在 emacs 中执行这样的转换？

原文

I would like to align all C++ class member names ( do not confuse with member types ) in one column.

Lets look at the example of what we have at entrance:

class Foo
{
public:
    void   method1( );
    int                  method2( ); 
    const Bar *        method3( ) const; 
protected:
    float    m_member;
};

and this is what we would like to have at the end:

class Foo
{
public:
    void           method1( );
    int            method2( ); 
    const Bar *    method3( ) const; 
protected:
    float          m_member;
};

So the longest member type declaration defines the column to which class member names will be aligned.
How can i perform such transformation in emacs ?

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