如何在asp.net(vb)中的button_click()中单击另一个按钮后使链接按钮可见

发布于 2024-09-01 17:41:07 字数 447 浏览 3 评论 0原文

如何在asp.net(vb)中的button_click()中单击另一个按钮后使链接按钮可见，

它显示错误为“对象引用未设置到对象的实例”。

我在我的代码中完成了此操作

Protected Sub InsertButton_Click(ByVal sender As Object, ByVal e As System.EventArgs)

    Dim receipt As LinkButton = FormView1.FindControl("LinkButton1")

   ' receipt.Enabled = "true"
   ' receipt.EnableTheming = "true"
   ' receipt.EnableViewState = "true"
    receipt.Visible = "true"

End Sub

原文

How to make a link button visible after another button has been clicked in asp.net(vb) in button_click()

it says error as "Object reference not set to an instance of an object."

i've done this in my code

Protected Sub InsertButton_Click(ByVal sender As Object, ByVal e As System.EventArgs)

    Dim receipt As LinkButton = FormView1.FindControl("LinkButton1")

   ' receipt.Enabled = "true"
   ' receipt.EnableTheming = "true"
   ' receipt.EnableViewState = "true"
    receipt.Visible = "true"

End Sub

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水染的天色ゝ 2024-09-08 17:41:07

删除表单名称，如下所示：

Dim receipt As LinkButton = FindControl("LinkButton1")
If (Not receipt Is Nothing)
   ' receipt.Enabled = "true"
   ' receipt.EnableTheming = "true"
   ' receipt.EnableViewState = "true"
    receipt.Visible = "true"
End if

Remove the form name like this:

Dim receipt As LinkButton = FindControl("LinkButton1")
If (Not receipt Is Nothing)
   ' receipt.Enabled = "true"
   ' receipt.EnableTheming = "true"
   ' receipt.EnableViewState = "true"
    receipt.Visible = "true"
End if

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