PHP:测试两个双变量会在不更改变量的情况下给出不同的结果

发布于 2024-09-01 17:35:46 字数 1272 浏览 1 评论 0原文

在我的代码中我有两个双精度值。我们称它们为 $a$b。现在我想测试一下哪一个更大,所以我写了以下内容:

print ($a > $b ? "larger\n" : "smaller\n");
print ($a > $b ? "larger\n" : "smaller\n");

奇怪的结果是

larger
smaller

有人以前遇到过类似的问题吗?这个问题只出现在我们使用php-cgi的嵌入式linux系统上。

感谢您的回答和建议。

这是整个代码:我需要将十六进制值解码为关于符号的十进制值,并最终使用大于整数大小的数字

function decodeInteger($datahex)
{
    // ignore non hex characters
    $hex = preg_replace('/[^0-9A-Fa-f]/', '', $datahex);

    // converted decimal value as double:
    $dec = hexdec($hex) * 1.0;

    // maximum decimal value based on length of hex + 1:
    //   number of bits in hex number is 8 bits for each 2 hex-characters -> max = 2^n
    //   use 'pow(2.0,n)' since '1 << n' and 'pow(2,n)' is only for integers and therefore limited to integer size.
    $max = pow(2.0, 4 * (strlen($hex) + (strlen($hex) % 2)));

    // complement = maximum - converted hex:
    $_dec = $max - $dec;


    print ($dec > $_dec ? "larger\n" : "smaller\n");
    print ($dec > $_dec ? "larger\n" : "smaller\n");

    // if dec value is larger than its complement we have a negative value (first bit is set)
    return $dec > $_dec ? -$_dec : $dec;
}

in my code i have two double values. Lets call them $a and $b. now I want to test which one of them is larger, so I wrote the following:

print ($a > $b ? "larger\n" : "smaller\n");
print ($a > $b ? "larger\n" : "smaller\n");

strangely the result is

larger
smaller

does anybody encountered a similar problem before? This problem only appears on our embedded linux system using php-cgi.

Thanks for your answers and advices.

Here is the whole code: I need to decode a hex value into a decimal value regarding the sign and eventually useng numbers larger than the integer-size

function decodeInteger($datahex)
{
    // ignore non hex characters
    $hex = preg_replace('/[^0-9A-Fa-f]/', '', $datahex);

    // converted decimal value as double:
    $dec = hexdec($hex) * 1.0;

    // maximum decimal value based on length of hex + 1:
    //   number of bits in hex number is 8 bits for each 2 hex-characters -> max = 2^n
    //   use 'pow(2.0,n)' since '1 << n' and 'pow(2,n)' is only for integers and therefore limited to integer size.
    $max = pow(2.0, 4 * (strlen($hex) + (strlen($hex) % 2)));

    // complement = maximum - converted hex:
    $_dec = $max - $dec;


    print ($dec > $_dec ? "larger\n" : "smaller\n");
    print ($dec > $_dec ? "larger\n" : "smaller\n");

    // if dec value is larger than its complement we have a negative value (first bit is set)
    return $dec > $_dec ? -$_dec : $dec;
}

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寂寞陪衬 2024-09-08 17:35:46

请运行

var_dump($dec); var_dump($_dec); var_dump($dec); var_dump($_dec);
print ($dec > $_dec ? "larger\n" : "smaller\n");

var_dump($dec); var_dump($_dec); var_dump($dec); var_dump($_dec);
print ($dec > $_dec ? "larger\n" : "smaller\n");

并在此处发布输出。 (很抱歉将此作为答案发布,但我的 Stackoverflow 声誉还不允许发表评论)

Please run

var_dump($dec); var_dump($_dec); var_dump($dec); var_dump($_dec);
print ($dec > $_dec ? "larger\n" : "smaller\n");

var_dump($dec); var_dump($_dec); var_dump($dec); var_dump($_dec);
print ($dec > $_dec ? "larger\n" : "smaller\n");

and post the output here. (sorry for posting this as an answer, but my Stackoverflow Reputation does not allow for comments, yet)

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