如何动态更改path_to()？

Question

我目前有三种方法，我想将其合并为一种：

  def send_email(contact,email)

  end

  def make_call(contact, call)
    return link_to "Call", new_contact_call_path(:contact => contact, :call => call, :status => 'called')
  end

  def make_letter(contact, letter)
    return link_to "Letter", new_contact_letter_path(:contact => contact, :letter => letter, :status => 'mailed')
  end

我想将这三种方法合并为一种，这样我就可以将模型作为参数之一传递，并且它仍然会正确创建 path_to。我试图用以下方法来做到这一点，但卡住了：

  def do_event(contact, call_or_email_or_letter)
    model_name = call_or_email_or_letter.class.name.tableize.singularize
   link_to "#{model_name.camelize}", new_contact_#{model_name}_path(contact, call_or_email_or_letter)" 
  end

感谢这里的答案，我尝试了以下方法，这让我更接近：

link_to( "#{model_name.camelize}", send("new_contact_#{model_name}_path", 
                                        :contact => contact, 
                                        :status => "done",
                                        :model_name => model_name) )

但我似乎不知道如何过去 #{model_name} :attribute，然后发送 model_name 的值，不是作为字符串，而是引用对象。

我成功了：——给 Kadada 点分，因为他让我朝着正确的方向前进:)

  def do_event(contact, call_or_email_or_letter) 
    model_name = call_or_email_or_letter.class.name.tableize.singularize 
    link_to( "#{model_name.camelize}", send("new_contact_#{model_name}_path", 
                                            :contact => contact, 
                                            :status => 'done',
                                            :"#{model_name}" => call_or_email_or_letter ) )                                       
  end 

Answer 1

试试这个：

def do_event(contact, call_or_email_or_letter)
  model_name = call_or_email_or_letter.class.name.tableize.singularize
  link_to( "#{model_name.camelize}", send("new_contact_#{model_name}_path", 
                 contact, call_or_email_or_letter) )
end