matplotlib - 斑马条纹图形的背景颜色？

发布于 2024-08-31 20:10:58 字数 346 浏览 1 评论 0原文

我正在使用 matplotlib 构建一个简单的折线图，并且我想在图表的背景上添加斑马条纹，以便每个交替行的颜色都不同。有办法做到这一点吗？

我的图表已经有网格，并且只有主要刻度。

编辑：来自我下面评论的代码，但更清晰：

yTicks = ax.get_yticks()[:-1]
xTicks = ax.get_xticks()
ax.barh(yTicks, [max(xTicks)-min(xTicks)] * len(yTicks),
    height=(yTicks[1]-yTicks[0]), left=min(xTicks), color=['w','#F0FFFF'])

原文

I'm building a simple line chart with matplotlib, and I'd like to zebra-stripe the background of the chart, so that each alternating row is colored differently. Is there a way to do this?

My chart already has gridding, and has major ticks only.

Edit: The code from my comment below, but more legible:

yTicks = ax.get_yticks()[:-1]
xTicks = ax.get_xticks()
ax.barh(yTicks, [max(xTicks)-min(xTicks)] * len(yTicks),
    height=(yTicks[1]-yTicks[0]), left=min(xTicks), color=['w','#F0FFFF'])

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初懵 2024-09-07 20:10:58

这是一个使用条形图（axes.barh）来模拟条带化的快速技巧。

import matplotlib.pyplot as plt

# initial plot
fig = plt.figure()
ax = fig.add_subplot(111)
ax.plot([1,2,3,4,5])

yTickPos,_ = plt.yticks()
yTickPos = yTickPos[:-1] #slice off the last as it is the top of the plot
# create bars at yTickPos that are the length of our greatest xtick and have a height equal to our tick spacing
ax.barh(yTickPos, [max(plt.xticks()[0])] * len(yTickPos), height=(yTickPos[1]-yTickPos[0]), color=['g','w'])

plt.show()

产生：

Here's a quick hack that uses a barchart (axes.barh) to simulate striping.

import matplotlib.pyplot as plt

# initial plot
fig = plt.figure()
ax = fig.add_subplot(111)
ax.plot([1,2,3,4,5])

yTickPos,_ = plt.yticks()
yTickPos = yTickPos[:-1] #slice off the last as it is the top of the plot
# create bars at yTickPos that are the length of our greatest xtick and have a height equal to our tick spacing
ax.barh(yTickPos, [max(plt.xticks()[0])] * len(yTickPos), height=(yTickPos[1]-yTickPos[0]), color=['g','w'])

plt.show()

Produces:

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