Django使模型字段名称成为链接
我想要做的是在模型的字段名称上有一个链接。因此，当我使用管理界面填写表单时，我可以访问一些信息。
我知道这不起作用，但显示了我想要做的
class A(models.Model):
item_type = models.CharField(max_length=100, choices=ITEMTYPE_CHOICES, verbose_name="<a href='http://www.quackit.com/html/codes'>Item Type</a>")
其他选项是在该字段旁边添加描述。
我什至不知道从哪里开始。
what Im looking to do is to have a link on the name of a field of a model. So when im filling the form using the admin interface i can access some information.
I know this doesn't work but shows what i want to do
class A(models.Model):
item_type = models.CharField(max_length=100, choices=ITEMTYPE_CHOICES, verbose_name="<a href='http://www.quackit.com/html/codes'>Item Type</a>")
Other option would be to put a description next to the field.
Im not even sure where to start from.
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遗憾的是，这比乍一看要困难得多。从您定义
verbose_name的时间点到它到达admin/includes/fieldset.html{{ field.label_tag }} 的时间之间> 模板，该字符串会发生很多操作。本质上，无论您做什么，字符串都会被强制返回 unicode 并（最终）在label_tag中转义。尝试使用mark_safe或SafeUnicode甚至|safe模板过滤器都无法防止发生转义。这意味着您有三个选择：
在 django 表单内部进行大量的黑客攻击，以毫发无伤地携带 SafeUnicode 字符串。
在
admin/includes/fieldset.html模板中手动构建字段的标签标记。请注意，该标签上有很多重要属性，例如 id、for、class 等。创建一个模板过滤器，用于解析标签标记内的字符串并将其转换为链接。
如果您擅长正则表达式，选项三实际上可能是最简单的。
Sadly, this is a lot harder than at first glance. Between the point at which you define
verbose_nameand the time it gets to{{ field.label_tag }}in theadmin/includes/fieldset.htmltemplate, a lot of manipulations happen to that string. Essentially no matter what you do, the string gets forced back into unicode and (ultimately) escaped inlabel_tag. Trying to usemark_safeorSafeUnicodeor even the|safetemplate filters all fail to prevent the escaping that takes place.What that means is that you have three options:
Do a lot of hacking in the django form internals to carry a SafeUnicode string all the way through unharmed.
Manually construct the field's label tag in the
admin/includes/fieldset.htmltemplate. Beware that there are a lot of important attributes that go on that label like id, for, class, etc.Create a template filter that parses the string inside the label tag and converts it into a link for you.
Option three there may actually be the simplest if you're any good at all with regexes.
这是真正应该在模板中处理的事情。
这是一种解决方法......
您可以创建一个名为“描述”的完整其他模型，然后将“项目类型”作为该表中的条目。
从那里，您可以查看永久链接装饰器 http ://docs.djangoproject.com/en/dev/ref/models/instances/#the-permalink-decorator 这将允许您创建任何给定“描述”对象的永久链接。
最后，查看 http://docs.djangoproject .com/en/1.1/ref/contrib/admin/#overriding-admin-templates 用于修改管理模板。在编辑
A 类对象时，您可以将锚点插入该描述对象的永久链接。您想做的事情绝对是可能的。你只需要重新整理一下你的想法。
祝你好运！
This is something that should really be handled in the template.
Here's one way to go about it...
You can make a whole other model called "Description", then make "Item Type" as an entry in that table.
From there, you can check out the permalink decorator http://docs.djangoproject.com/en/dev/ref/models/instances/#the-permalink-decorator which will allow you to create permalinks to any given "Description" object.
Finally, look into http://docs.djangoproject.com/en/1.1/ref/contrib/admin/#overriding-admin-templates for modifying admin templates. Where you are editing the
class Aobjects, you can insert an anchor to the permalink of that Description object.What you are looking to do is definitely possible. You just need to reorganize your thinking.
Good luck!