给定边界框为纬度/经度并且“点”为坐标，如何在 ESRI 折线中绘制点作为弧度？
我正在使用 OpenMap 并使用 com.bbn.openmap.layer.shape.ShapeFile 读取 ShapeFile。边界框以纬度/经度点的形式读取，例如 39.583642,-104.895486。边界框是左下点和右上角点，表示包含点的位置。在 OpenMap 中称为“弧度”的“点”采用不同的格式，如下所示：[0.69086486, -1.8307719, 0.6908546, -1.8307716, 0.6908518, -1.8307717, 0.69085056, -1.8307722, 084936,-1.8307728 、0.6908477、-1.8307738、0.69084626、-1.8307749、0.69084185、-1.8307792]。
如何将“0.69086486，-1.8307719”等点转换为可在普通图形中使用的x，y坐标？
我相信这里所需要的只是某种转换，因为将这些点带入 Excel 并绘制它们的图形会创建一条曲线与给定位置（纬度/经度）的道路曲线相匹配的线。但是，轴需要手动调整，并且我没有关于如何调整轴的参考，因为给定的边界框似乎与给定点的格式不同。
ESRI Shapefile技术描述似乎没有提到这一点（http://www .esri.com/library/whitepapers/pdfs/shapefile.pdf）。
I'm using OpenMap and I'm reading a ShapeFile using com.bbn.openmap.layer.shape.ShapeFile. The bounding box is read in as lat/long points, for example 39.583642,-104.895486. The bounding box is a lower-left point and an upper-right point which represents where the points are contained. The "points," which are named "radians" in OpenMap, are in a different format, which looks like this: [0.69086486, -1.8307719, 0.6908546, -1.8307716, 0.6908518, -1.8307717, 0.69085056, -1.8307722, 0.69084936, -1.8307728, 0.6908477, -1.8307738, 0.69084626, -1.8307749, 0.69084185, -1.8307792].
How do I convert the points like "0.69086486, -1.8307719" into x,y coordinates that are usable in normal graphics?
I believe all that's needed here is some kind of conversion, because bringing the points into Excel and graphing them creates a line whose curve matches the curve of the road at the given location (lat/long). However, the axises need to be adjusted manually and I have no reference as how to adjust the axises, since the given bounding box appears to be in a different format than the given points.
The ESRI Shapefile technical description doesn't seem to mention this (http://www.esri.com/library/whitepapers/pdfs/shapefile.pdf).
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0.69086486, -1.8307719是以弧度表示的纬度和经度。首先，转换为度数（乘以 (180/pi)），然后您的边界框和坐标之间将具有通用单位。
然后，您可以使用以下内容在本地框架中绘制所有内容：
(latitude0, longitude0) 是参考点的坐标（例如边界框的左下角）
角度单位为度，距离单位为米
编辑 - 解释：
这是地球的正投影，被视为半径为 6378137.0 m（WGS84 椭球的半长轴）的球体，以点 (lat0, lon0) 为中心
0.69086486, -1.8307719is a latitude and a longitude in radians.First, convert to degrees (multiply by (180/pi)), then you will have common units between your bounding box and your coordinates.
Then you can plot all of it in a local frame with the following :
(latitude0, longitude0) are the coordinates of a reference point (e.g. the lower-left corner of the bounding box)
units are degrees for angles and meters for distances
Edit -- explanation :
This is an orthographic projection of the Earth considered as a sphere whose radius is 6378137.0 m (semi-major axis of the WGS84 ellipsoid), centered on the point (lat0, lon0)
在 OpenMap 中，有多种方法可以将弧度转换为十进制：
对于数组，可以使用 ProjMath.arrayDegToRad(double[] radvals);
小心最后一个，它会就地进行转换。因此，如果您从 OMPoly 获取纬度/经度数组，请在转换之前先复制它。否则，您将弄乱 OMPoly 的内部坐标，它预计以弧度为单位。
In OpenMap, there are a number of ways to convert from radians to decimal degrees:
For an array, you can use ProjMath.arrayDegToRad(double[] radvals);
Be careful with that last one, it does the conversion in place. So if you grab a lat/lon array from an OMPoly, make a copy of it first before converting it. Otherwise, you'll mess up the internal coordinates of the OMPoly, which it expects to be in radians.