python套接字问题
我写了这个Python代码：
import socks
import socket
socks.setdefaultproxy(socks.PROXY_TYPE_SOCKS5, "64.83.219.7", 58279)
socket.socket = socks.socksocket
socket.setdefaulttimeout(19)
import urllib2
print urllib2.urlopen('http://www.google.com').read()
但是当我执行它时，我得到这个错误：
urllib2.URLError: <urlopen error timed out>
我做错了什么？
I write this python code:
import socks
import socket
socks.setdefaultproxy(socks.PROXY_TYPE_SOCKS5, "64.83.219.7", 58279)
socket.socket = socks.socksocket
socket.setdefaulttimeout(19)
import urllib2
print urllib2.urlopen('http://www.google.com').read()
but when I execute it, I get this error:
urllib2.URLError: <urlopen error timed out>
What am I doing wrong?
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评论（1）
您的脚本中出现超时。我猜想由于代理设置错误而连接到谷歌。我认为您的目标是通过代理获取 http://www.google.com 的内容？
我不知道使用套接字/袜子模块设置它的方法。也许您想查看 python 文档中的以下章节：
http://docs.python.org/library/urllib2.html?highlight=urllib2#examples（代码sinppet 5和上面的文本）
http://docs.python.org/library/urllib2.html?highlight=urllib2#urllib2.Request.set_proxy
http://docs.python.org/library/urllib2 .html?highlight=urllib2#proxyhandler-objects
Something timed out in your script. I guess the connection to google because of wrong proxy setup. I think your goal is to fetch the contents of http://www.google.com through a proxy?
I don't know about this method to set it using socket/socks module. Maybe you want to take a look at the following chapters in the python documentation:
http://docs.python.org/library/urllib2.html?highlight=urllib2#examples (code sinppet 5 and the text above)
http://docs.python.org/library/urllib2.html?highlight=urllib2#urllib2.Request.set_proxy
http://docs.python.org/library/urllib2.html?highlight=urllib2#proxyhandler-objects